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Give the spin only formula fór calculati...

Give the spin only formula fór calculating the magnetic moment of a transition metal ion?

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.mu=sqrt(n(n+2). where, .n. is the rumber of un: paired electrons.
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Magnetic moments arise due to the presence of unpaired electrons’ Calculated magnetic moments of two transition metal ions are given below: Justify these observations on the basis of spin only formula.

Presence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e., mu = sqrt(n(n+2)) where n=number of unpaired electrons and mu =magnetic momentin (in Bohr magneton, B.M.). If n=1, then mu = 1.73 B.M . The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it is:

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The observed magnetic of Sc^(3+) was found to be zero. Calculate the magnetic moment of Sc^(3+) using the ‘spin only’ formula and compare the resuit of observed and calculated magnetic moment.

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V PUBLICATION-THE d- AND f- BLOCK ELEMENTS-QUESTION BANK
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  2. Why the transition metal compounds are coloured?

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  5. . Name the metal, with highest melting point?

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  8. What is the reaction between KMnO(4) and sodium thiosulphate?

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  9. Potassium permanganate KMnO(4) is not a primary standard Why?

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  10. Actinoids show, a large number of oxidation states Why?

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  11. Write the reason for the statement given below: Transition elements sh...

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  15. Which is more basic LaOH(3) or LuOH(3) . Why?

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  16. Why Sm^(2+), Eu^(2+) and Yb^(2+) in solutions 'are good reducing agen...

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  17. Why is the third ionisation energy of manganese (At No. 25) unexpected...

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