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Give the spin only formula fór calculati...

Give the spin only formula fór calculating the magnetic moment of a transition metal ion?

Text Solution

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.mu=sqrt(n(n+2). where, .n. is the rumber of un: paired electrons.
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Magnetic moments arise due to the presence of unpaired electrons’ Calculated magnetic moments of two transition metal ions are given below: Justify these observations on the basis of spin only formula.

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Knowledge Check

  • Presence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e., mu = sqrt(n(n+2)) where n=number of unpaired electrons and mu =magnetic momentin (in Bohr magneton, B.M.). If n=1, then mu = 1.73 B.M . The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it is:

    A
    2
    B
    3
    C
    4
    D
    5
  • Effective magnetic moment of 'Sc^((3+))' ion is

    A
    1.73 BM'
    B
    0
    C
    5.92 BM'
    D
    2.83 BM'
  • Effective magnetic moment of Sc^(3+) ion is :

    A
    ` 1.73`
    B
    ` 0`
    C
    ` 5.92`
    D
    ` 2.83`
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