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Correct order of bond strength for the f...

Correct order of bond strength for the following molecule or
ions is :

A

`O_(2)^(-)gtO_(2)^(+)gtO_(2)`

B

`O_(2)gtO_(2)^(+)gtO_(2)^(-)`

C

`O_(2)gtO_(2)^(-)gtO_(2)^(+)`

D

`O_(2)^(+)gtO_(2)gtO_(2)^(-)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the correct order of bond strength for the molecules or ions O2, O2+, and O2-, we will use molecular orbital theory to calculate the bond order for each species. The bond strength is directly proportional to the bond order. ### Step-by-Step Solution: 1. **Determine the Electron Configuration of O2:** - The molecular orbital configuration for O2 is: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi^*_{2p_x}^1 \pi^*_{2p_y}^1 \] - Count the bonding and antibonding electrons: - Bonding electrons (nB) = 10 - Antibonding electrons (nA) = 2 2. **Calculate the Bond Order for O2:** - Bond order is calculated using the formula: \[ \text{Bond Order} = \frac{1}{2} (nB - nA) \] - For O2: \[ \text{Bond Order} = \frac{1}{2} (10 - 2) = \frac{1}{2} \times 8 = 4 \] 3. **Determine the Electron Configuration of O2+:** - O2+ has one less electron than O2. The electron is removed from the antibonding orbital: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi^*_{2p_x}^1 \] - Count the bonding and antibonding electrons: - Bonding electrons (nB) = 10 - Antibonding electrons (nA) = 1 4. **Calculate the Bond Order for O2+:** - For O2+: \[ \text{Bond Order} = \frac{1}{2} (10 - 1) = \frac{1}{2} \times 9 = 4.5 \] 5. **Determine the Electron Configuration of O2-:** - O2- has one additional electron compared to O2. The electron is added to the antibonding orbital: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi^*_{2p_x}^2 \pi^*_{2p_y}^0 \] - Count the bonding and antibonding electrons: - Bonding electrons (nB) = 10 - Antibonding electrons (nA) = 3 6. **Calculate the Bond Order for O2-:** - For O2-: \[ \text{Bond Order} = \frac{1}{2} (10 - 3) = \frac{1}{2} \times 7 = 3.5 \] 7. **Summarize the Bond Orders:** - O2: Bond Order = 4 - O2+: Bond Order = 4.5 - O2-: Bond Order = 3.5 8. **Determine the Order of Bond Strength:** - The order of bond strength based on bond order is: \[ O2^+ > O2 > O2^- \] ### Final Answer: The correct order of bond strength is: **O2+ > O2 > O2-**

To determine the correct order of bond strength for the molecules or ions O2, O2+, and O2-, we will use molecular orbital theory to calculate the bond order for each species. The bond strength is directly proportional to the bond order. ### Step-by-Step Solution: 1. **Determine the Electron Configuration of O2:** - The molecular orbital configuration for O2 is: \[ \sigma_{1s}^2 \sigma^*_{1s}^2 \sigma_{2s}^2 \sigma^*_{2s}^2 \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi^*_{2p_x}^1 \pi^*_{2p_y}^1 ...
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