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A vessel of volume 2 xx 10^(-2) m^(3) co...

A vessel of volume `2 xx 10^(-2) m^(3)` contains a mixture of hydrogen and helium at `47^(@)C` temperature and `4.15 xx 10^(5) N//m^(2)` Pressure. The mass of the mixture is `10^(-2) kg`. Calculate the masses of hydrogen and helium in the given mixture.

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To solve the problem of finding the masses of hydrogen and helium in the given mixture, we will use the ideal gas equation and some algebraic manipulations. Here’s a step-by-step breakdown of the solution: ### Step 1: Write down the known values - Volume \( V = 2 \times 10^{-2} \, m^3 \) - Temperature \( T = 47^\circ C = 47 + 273 = 320 \, K \) - Pressure \( P = 4.15 \times 10^5 \, N/m^2 \) - Total mass of the mixture \( m_1 + m_2 = 10^{-2} \, kg = 10 \, g \) ...
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