On moving a charge of 20 C by 2 cm, 2 J ...

On moving a charge of 20 C by 2 cm, 2 J of work is done, then the potential differ rence between the point is :

0.1 V

0.5V

Text Solution

Verified by Experts

The correct Answer is:

By definition of electrostatic potential energy
`DeltaU=q DeltaV`
`DeltaV=(DeltaU)/q=2/20=0.1 V`

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