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The electric field associated with a monochromatic beam of light becomes zero, `1.2xx10^15` times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0eV, `h=6.63xx10^(-34)Js`.

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The correct Answer is:
`(0.6xx10^(15)h-2e)J=0.48eV`
frequency of the light
`=(1)/(2)xx1.2xx10^(15)=0.6xx10^(15)Hz`
`KE=hv - phi=0.48 eV`
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