Which of the following statements is`//` are correct ?
`(I)` White precipitate of `Zn(OH)_(2)` is soluble in excess ammonia
and in solutions of ammonium salts.
`(II)` Yellow precipitate of barium chromate is soluble in dilute
acetic acid as well as in mineral acids.
`(III)` Green precipitate of `Ni(OH)_(2)` is soluble in excess sodium hydroxide.

Options

A. only `(I)`
B. only `(I)` and `(II)`
C. only `(II)` and `(III)`
D. all

Explanation

To determine which of the statements are correct, we will evaluate each statement one by one.

### Step 1: Evaluate Statement I
**Statement I:** White precipitate of Zn(OH)₂ is soluble in excess ammonia and in solutions of ammonium salts.

- **Explanation:** Zinc hydroxide (Zn(OH)₂) is indeed a white precipitate that can dissolve in excess ammonia. When Zn(OH)₂ reacts with ammonia, it forms a soluble complex, [Zn(NH₃)₄]²⁺. This indicates that the statement is correct.

**Conclusion:** Statement I is correct.

### Step 2: Evaluate Statement II
**Statement II:** Yellow precipitate of barium chromate is soluble in dilute acetic acid as well as in mineral acids.

- **Explanation:** Barium chromate (BaCrO₄) is a yellow precipitate that is generally considered insoluble in dilute acetic acid and mineral acids. Therefore, this statement is false.

**Conclusion:** Statement II is incorrect.

### Step 3: Evaluate Statement III
**Statement III:** Green precipitate of Ni(OH)₂ is soluble in excess sodium hydroxide.

- **Explanation:** Nickel hydroxide (Ni(OH)₂) is a green precipitate that is not soluble in excess sodium hydroxide. Instead, it remains insoluble. Thus, this statement is also false.

**Conclusion:** Statement III is incorrect.

### Final Conclusion
Only Statement I is correct. Therefore, the answer is that only Statement I is true.

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