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Which of the following correctly represe...

Which of the following correctly represent the equivalent conductivity `(^^_(N))` and molar conductivity `(^^_(M))` of aluminium sulphate where equivalent conductivities of `Al^(+3)` and `SO_(4)^(-2)` are `lamda_(1)` and `lamda_(2)` respectively?

A

.^^_(N)=lamda_(1)+lamda_(2)`

B

.^^_(M)=3lamda_(1)+2lamda_(2)`

C

.^^_(N)=(lamda_(1))/(3)+(lamda_(2))/(2)`

D

.^^_(M)=6lamda_(1)+6lamda_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the equivalent conductivity (λₙ) and molar conductivity (λₘ) of aluminum sulfate (Al₂(SO₄)₃), we will follow these steps: ### Step 1: Understand the dissociation of aluminum sulfate Aluminum sulfate dissociates in water to produce aluminum ions (Al³⁺) and sulfate ions (SO₄²⁻). The balanced equation for this dissociation is: \[ \text{Al}_2(\text{SO}_4)_3 \rightarrow 2 \text{Al}^{3+} + 3 \text{SO}_4^{2-} \] ### Step 2: Define equivalent conductivity (λₙ) Equivalent conductivity (λₙ) is defined as the conductivity of a solution containing one gram equivalent of the solute. For aluminum sulfate, it can be expressed as: \[ \lambda_n = \lambda_1 + \lambda_2 \] where: - λ₁ = equivalent conductivity of Al³⁺ - λ₂ = equivalent conductivity of SO₄²⁻ ### Step 3: Define molar conductivity (λₘ) Molar conductivity (λₘ) is defined as the conductivity of a solution containing one mole of the solute. For aluminum sulfate, it can be expressed as: \[ \lambda_m = 2\lambda_1 + 3\lambda_2 \] Here, the coefficients (2 and 3) correspond to the number of moles of Al³⁺ and SO₄²⁻ produced from one mole of aluminum sulfate. ### Step 4: Write the final expressions From the above definitions, we have: - Equivalent conductivity: \[ \lambda_n = \lambda_1 + \lambda_2 \] - Molar conductivity: \[ \lambda_m = 2\lambda_1 + 3\lambda_2 \] ### Step 5: Identify the correct option Based on the derived expressions for equivalent and molar conductivities, we can check the options provided in the question to find the correct representation. ### Summary of the solution: 1. **Equivalent conductivity (λₙ)**: \( \lambda_n = \lambda_1 + \lambda_2 \) 2. **Molar conductivity (λₘ)**: \( \lambda_m = 2\lambda_1 + 3\lambda_2 \)
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