For reaction `NH_(3)(liq.)+Naoverset(warm)toP+Quarr` Incorrect
statement is:

Options

A. Hydrolysis of `P` produces `NH_(3)` gas.
B. Gas `Q` reacts with heated alkali metals.
C. Anionic part of `P` is weaker base than `NH_(3)`
D. Gas Q is also produced, when Li metal is heated with `NH_(3)` gas

Explanation

To solve the question regarding the reaction of liquid ammonia (NH₃) with sodium (Na) and to identify the incorrect statement, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction between liquid ammonia and sodium can be represented as:
\[ \text{NH}_3 (l) + \text{Na} \overset{\text{warm}}{\rightarrow} \text{NaNH}_2 + \frac{1}{2} \text{H}_2 (g) \]
Here, NaNH₂ is the product P and H₂ is the gas evolved Q.

**Hint**: Understand the products formed in the reaction and their states (solid, liquid, gas).

2. **Analyze Each Statement**:
We need to evaluate the given statements one by one to identify which one is incorrect.

- **Statement 1**: Hydrolysis of P produces NH₃ gas.
- When NaNH₂ reacts with water, it produces NaOH and NH₃:
\[ \text{NaNH}_2 + \text{H}_2\text{O} \rightarrow \text{NaOH} + \text{NH}_3 \]
- This statement is **correct**.

**Hint**: Check the products of hydrolysis reactions to confirm the statement.

- **Statement 2**: Gas Q reacts with alkali metals.
- Hydrogen gas (H₂) can react with alkali metals to form metal hydrides:
\[ 2\text{Na} + \text{H}_2 \rightarrow 2\text{NaH} \]
- This statement is **correct**.

**Hint**: Recall the reactivity of hydrogen with alkali metals.

- **Statement 3**: Anionic part of P is a weaker base than ammonia.
- The anionic part of NaNH₂ is NH₂⁻, which is the conjugate base of NH₃. NH₂⁻ is a stronger base than NH₃ because it can accept a proton to form NH₃:
\[ \text{NH}_2^- + \text{H}^+ \rightarrow \text{NH}_3 \]
- This statement is **incorrect**.

**Hint**: Compare the strength of bases by looking at their conjugate acids.

- **Statement 4**: Gas Q is also produced when Li metal is heated with ammonia gas.
- Lithium reacts with ammonia to produce hydrogen gas:
\[ \text{Li} + \text{NH}_3 \rightarrow \text{LiNH}_2 + \frac{1}{2} \text{H}_2 \]
- This statement is **correct**.

**Hint**: Review the reactions of alkali metals with ammonia.

3. **Conclusion**:
The incorrect statement is:
- **Anionic part of P (NH₂⁻) is weaker base than ammonia (NH₃)**.

### Final Answer:
The incorrect statement is: "Anionic part of P is weaker base than the ammonia."