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Compare the radii of two nuclei with mas...

Compare the radii of two nuclei with mass number 125 and 64 respectively.

A

5/2

B

5/3

C

5/4

D

3/5

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To compare the radii of two nuclei with mass numbers 125 and 64, we can use the formula for the radius of a nucleus, which is given by: \[ r = r_0 A^{1/3} \] where: - \( r \) is the radius of the nucleus, - \( r_0 \) is a constant (approximately \( 1.2 \, \text{fm} \)), - \( A \) is the mass number of the nucleus. ### Step-by-Step Solution: 1. **Identify the mass numbers**: - Let \( A_1 = 125 \) (mass number of the first nucleus). - Let \( A_2 = 64 \) (mass number of the second nucleus). 2. **Write the formula for the radii**: - The radius of the first nucleus \( r_1 \) is given by: \[ r_1 = r_0 A_1^{1/3} \] - The radius of the second nucleus \( r_2 \) is given by: \[ r_2 = r_0 A_2^{1/3} \] 3. **Set up the ratio of the radii**: - To compare the two radii, we can find the ratio \( \frac{r_1}{r_2} \): \[ \frac{r_1}{r_2} = \frac{r_0 A_1^{1/3}}{r_0 A_2^{1/3}} = \frac{A_1^{1/3}}{A_2^{1/3}} \] - Here, the \( r_0 \) cancels out. 4. **Substitute the values of \( A_1 \) and \( A_2 \)**: - Substitute \( A_1 = 125 \) and \( A_2 = 64 \): \[ \frac{r_1}{r_2} = \frac{125^{1/3}}{64^{1/3}} = \left(\frac{125}{64}\right)^{1/3} \] 5. **Calculate \( \frac{125}{64} \)**: - Calculate \( \frac{125}{64} = \frac{5^3}{4^3} = \left(\frac{5}{4}\right)^3 \). 6. **Take the cube root**: - Now take the cube root: \[ \left(\frac{5}{4}\right)^{1} = \frac{5}{4} \] 7. **Conclusion**: - Thus, the ratio of the radii of the two nuclei is: \[ \frac{r_1}{r_2} = \frac{5}{4} \] - This means that the radius of the nucleus with mass number 125 is \( \frac{5}{4} \) times the radius of the nucleus with mass number 64.

To compare the radii of two nuclei with mass numbers 125 and 64, we can use the formula for the radius of a nucleus, which is given by: \[ r = r_0 A^{1/3} \] where: - \( r \) is the radius of the nucleus, - \( r_0 \) is a constant (approximately \( 1.2 \, \text{fm} \)), - \( A \) is the mass number of the nucleus. ...
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