Statement -1 : Hydrolysis of `NCl_(3)` gives `NH_(4)OH` and `HOCl` while `PCl_(3)` on hydrolysis gives `H_(3)PO_(3)` and HCl.
Statement -2 : The difference is due to the change in polarity of `P^(+sigma)-CI^(-sigma)` bond in `PCl_(3)` in contrast to `N^(-sigma)-CI^(+sigma)` bond in `NCl_(3)`.

Options

A. Statement -1 is true , Statement-2 is true, Statement-2 is a correct explantion for Statement -1.
B. Statement -1 is true, Statement- 2 is false.
C. Statement -1 is False, Statement- 2 is True.
D. Statement -1 and Statement- 2 both are False.

Explanation

To solve the problem, we need to analyze the hydrolysis of \(NCl_3\) and \(PCl_3\) and understand the differences in their products based on the polarity of the bonds involved.

### Step 1: Hydrolysis of \(NCl_3\)

1. **Write the hydrolysis reaction**:
\[ NCl_3 + 3H_2O \rightarrow NH_3 + 3HOCl \]

Here, \(NCl_3\) reacts with water to produce ammonia (\(NH_3\)) and hypochlorous acid (\(HOCl\)).

2. **Further hydrolysis of \(NH_3\)**:
\[ NH_3 + H_2O \rightarrow NH_4OH \]

Ammonia can further react with water to form ammonium hydroxide (\(NH_4OH\)).

### Step 2: Hydrolysis of \(PCl_3\)

1. **Write the hydrolysis reaction**:
\[ PCl_3 + 3H_2O \rightarrow H_3PO_3 + 3HCl \]

In this case, \(PCl_3\) reacts with water to produce phosphorous acid (\(H_3PO_3\)) and hydrochloric acid (\(HCl\)).

### Step 3: Analyze the Polarity of Bonds

1. **Polarity in \(NCl_3\)**:
- The electronegativity of nitrogen (N) is slightly higher than that of chlorine (Cl). This means that in the \(N-Cl\) bond, nitrogen has a partial negative charge (\(\delta^-\)) and chlorine has a partial positive charge (\(\delta^+\)).
- This polarity allows for the formation of \(NH_3\) and \(HOCl\) during hydrolysis.

2. **Polarity in \(PCl_3\)**:
- In \(PCl_3\), chlorine is more electronegative than phosphorus (P). Therefore, in the \(P-Cl\) bond, phosphorus has a partial positive charge (\(\delta^+\)) and chlorine has a partial negative charge (\(\delta^-\)).
- This difference in polarity leads to the formation of \(H_3PO_3\) and \(HCl\) during hydrolysis.

### Step 4: Conclusion

- **Statement 1**: The hydrolysis of \(NCl_3\) gives \(NH_4OH\) and \(HOCl\), while \(PCl_3\) gives \(H_3PO_3\) and \(HCl\). This statement is **true**.
- **Statement 2**: The difference is due to the change in polarity of \(P^{+\sigma}-Cl^{-\sigma}\) bond in \(PCl_3\) in contrast to \(N^{-\sigma}-Cl^{+\sigma}\) bond in \(NCl_3\). This statement is also **true** and explains the first statement.

Thus, both statements are true, and statement 2 is the correct explanation for statement 1.

### Final Answer:
Both statements are true, and statement 2 is the correct explanation for statement 1.

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