Which compound give `CO_(2)` with `NaHCO_(3)` ?

Options

A. Phenol
B. Glycerol
C. `n-`butanol
D. Acetic acid

Answer

To determine which compound gives \( CO_2 \) when reacted with \( NaHCO_3 \) (sodium bicarbonate), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant**: We know that \( NaHCO_3 \) is sodium bicarbonate, which is a weak base. It can react with acids to produce carbon dioxide gas.

2. **Consider Possible Acids**: The question asks for a compound that can release \( CO_2 \) upon reaction with \( NaHCO_3 \). Common acids that can do this include carboxylic acids, such as acetic acid (\( CH_3COOH \)).

3. **Write the Reaction**: Let's consider the reaction between acetic acid and sodium bicarbonate:
\[ CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + CO_2 + H_2O \]
In this reaction, acetic acid reacts with sodium bicarbonate to produce sodium acetate, carbon dioxide, and water.

4. **Analyze the Reaction**: The key point here is that carboxylic acids, like acetic acid, are stronger acids than carbonic acid. This means they can effectively react with the weak base \( NaHCO_3 \) to produce \( CO_2 \).

5. **Conclusion**: Since acetic acid is a carboxylic acid and reacts with sodium bicarbonate to produce \( CO_2 \), the answer to the question is:
- **Acetic Acid (\( CH_3COOH \))**.