Home
Class 12
CHEMISTRY
Compound (x)(m.f=C(7)H(8)N), on reaction...

Compound `(x)(m.f=C_(7)H_(8)N)`, on reaction with `NaNO_(2)` and conc. `HCl` at `O^(@)C` followed by `beta -` naphthol gives orange coloured dye. Compound `(x)` is `:`

A

B

C

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to identify the compound \( (x) \) with the molecular formula \( C_7H_8N \) that reacts with \( NaNO_2 \) and concentrated \( HCl \) at \( 0^\circ C \) to form an orange-colored azo dye when followed by \( \beta \)-naphthol. ### Step-by-Step Solution: 1. **Understanding the Reaction**: The reaction described involves an aromatic primary amine. This type of amine can react with sodium nitrite (\( NaNO_2 \)) and hydrochloric acid (\( HCl \)) to form a diazonium salt, which can then couple with \( \beta \)-naphthol to produce an azo dye. 2. **Identifying the Structure of Compound \( (x) \)**: The molecular formula \( C_7H_8N \) suggests that the compound is an aromatic primary amine. The simplest aromatic amine is aniline (\( C_6H_5NH_2 \)), which has a phenyl group attached to an amine group. To meet the molecular formula \( C_7H_8N \), we can add a methyl group (\( CH_3 \)) to the aniline structure. 3. **Possible Structures**: The methyl group can be attached to the benzene ring in three possible positions relative to the amine group: - **Ortho position**: \( C_6H_4(NH_2)(CH_3) \) (1,2-dimethylamine) - **Meta position**: \( C_6H_4(NH_2)(CH_3) \) (1,3-dimethylamine) - **Para position**: \( C_6H_4(NH_2)(CH_3) \) (1,4-dimethylamine) 4. **Reactivity with \( NaNO_2 \) and \( HCl \)**: All three structures are aromatic primary amines and will react with \( NaNO_2 \) and \( HCl \) to form the corresponding diazonium salts. 5. **Coupling with \( \beta \)-Naphthol**: The diazonium salt formed will then couple with \( \beta \)-naphthol to form an azo dye. The resulting azo dye will have an orange color, which is characteristic of azo compounds formed from such reactions. 6. **Conclusion**: Since all three structures can potentially lead to the formation of an azo dye, we need to identify which one is the correct compound \( (x) \) based on the options provided. - After analyzing the options, we find that **Option 2** corresponds to one of the possible structures of \( (x) \) that fits the criteria given in the question. ### Final Answer: The compound \( (x) \) is **Option 2**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • NITROGEN CONTAINING COMPOUNDS

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Nitrogen containing Compounds)|30 Videos
  • NITROGEN & OXYGEN FAMILY

    RESONANCE ENGLISH|Exercise Part-III Practice Test-2 (JEE (Advanced Pattern))|23 Videos
  • NUCLEAR CHEMISTRY

    RESONANCE ENGLISH|Exercise STAGE-II|1 Videos

Similar Questions

Explore conceptually related problems

Statement I: Aniline on reaction with NaNO_2 HCl at 0^@C followed by coupling with beta -naphthol gives a dark blue coloured precipitate. Statement II: The colour of the compound formed in the reaction of aniline with NaNO_2//HCl at 0^@C followed by coupling with beta -naphthol is due to extended conjugation.

How many toluidines on reaction with NaNO_(2)//HCl followed by H_(3)PO_(2) treatment gives Toluene.

A hydrocarbon 'A' (C_(4)H_(8)) on reaction HCl gives a compound 'B', (C_(4)H_(9)Cl) which on reaction with 1 mol of NH_(3) gives compounds 'C' (C_(4)H_(11)N) . On reacting with NaNO_(2) and HCl followed by treatment with water compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' given 2mols of acetyldehyde. Identify compound 'A' to 'D'. Explain the reaction involved.

An alkene (A)C_(16)H_(16) on ozonolysis gives only one product (B)(C_(8)H_(8)O) . Compound (B) on reaction with NH_(2)OH followed by reaction with H_(2)SO_(4), Delta gives N - methyl benzamide the compound 'A' is -

An organic compound A’ with molecular formula C_(7)H_(7)NO reacts with Br_(2) /aqKOH to give compound B’, which upon reaction with NaNO_(2) & HCl" at "O^(@) C gives C’. Compound C’ on heating with CH_(3)CH_(2)OH gives a hydrocarbon D’. Compound B’ on further reaction with Br_(2) water gives white precipitate of compound E’. Identify the compound A, B, C, D&E, also justify your answer by giving relevant chemical equations.

A hydrocarbon 'A', (C_4H_8) on reaction with HCl gives a compound 'B', (C_4H_9Cl) , which on reaction with 1 mol of NH_3 gives compound 'C', (C_4H_11N) . On reacting with NaNO_2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' gives 2 moles of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.

A hydrocarbon 'A', (C_4H_8) on reaction with HCl gives a compound 'B', (C_4H_9Cl) , which on reaction with 1 mol of NH_3 gives compound 'C', (C_4H_11N) . On reacting with NaNO_2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' gives 2 moles of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.

A hydrocarbon 'A', (C_4H_8) on reaction with HCl gives a compound 'B', (C_4H_9Cl) , which on reaction with 1 mol of NH_3 gives compound 'C', (C_4H_11N) . On reacting with NaNO_2 and HCl followed by treatment with water, compound 'C' yields an optically active alcohol, 'D'. Ozonolysis of 'A' gives 2 moles of acetaldehyde. Identify compounds 'A' to 'D'. Explain the reactions involved.

Which of the following compounds reacts with NaNO_2 and HCl at 0- 4^(@)C to give alcohol/phenol?

Compound (A) (C_(8)H_(8)O) on treatment with NH_(2)OH.HCl gives (B) and (C ). (B) and (C ) rearrange to give (D) and E, respectively, on treatment with acid. (B), (C ), (D), and (E ) are all isomers of molecular formula (C_(8)H_(9)NO) . When (D) is boiled with alcoholic KOH, an oil (F) (C_(6)H_(7)N) separates out. (F) reacts rapidly with CH_(3)COCl to give back (D). On the other hand, (E ) on boiling with alkali followed by acidification gives a white solid (G) (C_(7)H_(6)O_(2)) . Identify (A) to (G).