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18g of glucose (molar mass 180g "mol"^(-...

`18g` of glucose (molar mass `180g "mol"^(-1)`) is present in `500CM^(3)` of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

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To solve the problem step by step, we will calculate the molarity of the glucose solution first and then identify the additional data required to calculate the molality. ### Step 1: Calculate the number of moles of glucose To find the number of moles of glucose, we use the formula: \[ \text{Number of moles} = \frac{\text{mass of solute (g)}}{\text{molar mass (g/mol)}} \] ...
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Knowledge Check

  • What is the molarity of a solution containing 10 g of NaOH in 500 mL of solution ?

    A
    `"0.25 mol L"^(-1)`
    B
    `"0.75 mol L"^(-1)`
    C
    `"0.5 mol L"^(-1)`
    D
    `"1.25 mol L"^(-1)`
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