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18g of glucose (molar mass 180g "mol"^(-...

`18g` of glucose (molar mass `180g "mol"^(-1)`) is present in `500CM^(3)` of its aqueous solution. What is the molarity of the solution? What additional data is required if the molality of the solution is also required to be calculated?

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To solve the problem step by step, we will calculate the molarity of the glucose solution first and then identify the additional data required to calculate the molality. ### Step 1: Calculate the number of moles of glucose To find the number of moles of glucose, we use the formula: \[ \text{Number of moles} = \frac{\text{mass of solute (g)}}{\text{molar mass (g/mol)}} \] ...
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RESONANCE ENGLISH-SOLUTIONS-Board Level Exercise
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  19. 2.82g of glucose (molar mass =180) is dissolved in 30g of water. Calcu...

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  20. An aqueous solution freezes at 272.4 K while pure water freezes at 273...

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