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Statement-1: Due to adiabatic free expan...

Statement-1: Due to adiabatic free expansion temperature of real gas may increase.
Statement-2 : In adiabatic free expansion, temperature is always constant irrespective of real or ideal gas

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze both statements regarding adiabatic free expansion for ideal and real gases. ### Step-by-Step Solution: 1. **Understanding Adiabatic Free Expansion**: - In an adiabatic process, there is no heat exchange with the surroundings (Q = 0). - In free expansion, the gas expands into a vacuum, meaning there is no external pressure to do work against (W = 0). 2. **Applying the First Law of Thermodynamics**: - The first law of thermodynamics states: \[ Q = \Delta U + \Delta W \] - For adiabatic free expansion, since \(Q = 0\) and \(W = 0\), we have: \[ 0 = \Delta U + 0 \implies \Delta U = 0 \] 3. **Analyzing Ideal Gas**: - For an ideal gas, the change in internal energy (\(\Delta U\)) is related to temperature: \[ \Delta U = n \cdot C_v \cdot \Delta T \] - Since \(\Delta U = 0\), it implies: \[ \Delta T = 0 \] - Therefore, the temperature remains constant during adiabatic free expansion for an ideal gas. 4. **Analyzing Real Gas**: - For a real gas, while the work done is still zero and \(Q = 0\), the internal energy change (\(\Delta U\)) can depend on both temperature and volume. - Thus, \(\Delta U = 0\) does not necessarily imply \(\Delta T = 0\) for real gases. The temperature may change with volume changes, meaning: - The temperature of a real gas can either increase or decrease depending on its specific properties and the nature of the gas. 5. **Evaluating the Statements**: - **Statement 1**: "Due to adiabatic free expansion, the temperature of a real gas may increase." - This statement is **true** because the temperature can change in real gases during free expansion. - **Statement 2**: "In adiabatic free expansion, the temperature is always constant irrespective of real or ideal gas." - This statement is **false** because, while the temperature remains constant for ideal gases, it is not necessarily constant for real gases. ### Conclusion: - **Correct Answer**: Statement 1 is true, and Statement 2 is false. Thus, the correct answer is **C**.

To solve the question, we need to analyze both statements regarding adiabatic free expansion for ideal and real gases. ### Step-by-Step Solution: 1. **Understanding Adiabatic Free Expansion**: - In an adiabatic process, there is no heat exchange with the surroundings (Q = 0). - In free expansion, the gas expands into a vacuum, meaning there is no external pressure to do work against (W = 0). ...
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Knowledge Check

  • In an adiabatic expansion of an ideal gas -

    A
    (a) `W=-DeltaU`
    B
    (b) `W=DeltaU`
    C
    (c) `DeltaU=0`
    D
    (d) `W = 0 `
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