24 gm of Mg (At. mass 24) will produce MgO equal to:

Options

A. 2 mole
B. 1 mole
C. 3 mole
D. 4mole

Explanation

To solve the problem of how much magnesium oxide (MgO) is produced from 24 grams of magnesium (Mg), we can follow these steps:

### Step 1: Determine the number of moles of magnesium (Mg)
We know that the atomic mass of magnesium is 24 g/mol. To find the number of moles of magnesium in 24 grams, we can use the formula:

\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]

Substituting the values:

\[ \text{Number of moles of Mg} = \frac{24 \text{ g}}{24 \text{ g/mol}} = 1 \text{ mole} \]

### Step 2: Write the balanced chemical equation
The reaction between magnesium and oxygen to form magnesium oxide can be represented by the balanced chemical equation:

\[ 2 \text{Mg} + \text{O}_2 \rightarrow 2 \text{MgO} \]

From this equation, we can see that 2 moles of magnesium react with 1 mole of oxygen to produce 2 moles of magnesium oxide.

### Step 3: Determine the number of moles of magnesium oxide (MgO) produced
From the balanced equation, we can see that 1 mole of magnesium produces 1 mole of magnesium oxide. Since we have 1 mole of magnesium:

\[ \text{Number of moles of MgO produced} = 1 \text{ mole} \]

### Step 4: Calculate the mass of magnesium oxide (MgO) produced
To find the mass of magnesium oxide produced, we need to know the molar mass of magnesium oxide. The molar mass of MgO is calculated as follows:

\[ \text{Molar mass of MgO} = \text{Molar mass of Mg} + \text{Molar mass of O} = 24 \text{ g/mol} + 16 \text{ g/mol} = 40 \text{ g/mol} \]

Now, we can calculate the mass of magnesium oxide produced using the number of moles:

\[ \text{Mass of MgO} = \text{Number of moles} \times \text{Molar mass} = 1 \text{ mole} \times 40 \text{ g/mol} = 40 \text{ g} \]

### Conclusion
Thus, 24 grams of magnesium will produce 40 grams of magnesium oxide (MgO).