`{:("Column-I","Column-II"),((A)XeF_4,(p)sp^3d "see-saw geometry"),((B)SF_4,(q)sp^3d^2 "square planar"),((C )SF_6, (r)sp^3d^3 "distorted octahedral geometry"),((D)XeF_6,(s)sp^3d^2 "octahedral geometry"):}`

Explanation

To solve the given question, we need to determine the hybridization and geometry of the compounds listed in Column-I and match them with the options in Column-II. Let's go through each compound step by step.

### Step 1: Determine the hybridization and geometry of XeF₄
1. **Valence Electrons**: Xenon (Xe) has 8 valence electrons, and each fluorine (F) contributes 1 electron. Since there are 4 fluorine atoms, the total is:
\[ 8 + (4 \times 1) = 12 \text{ electrons} \]
2. **Hybridization Calculation**: The formula for hybridization is:
\[ \text{Hybridization} = \frac{\text{Valence Electrons} + \text{Monovalent Atoms} + \text{Negative Charges} - \text{Positive Charges}}{2} \]
Here, there are no charges, so:
\[ \text{Hybridization} = \frac{12}{2} = 6 \quad (\text{sp}^3d^2) \]
3. **Geometry**: With 4 bond pairs and 2 lone pairs, XeF₄ has a square planar geometry.

### Step 2: Determine the hybridization and geometry of SF₄
1. **Valence Electrons**: Sulfur (S) has 6 valence electrons, and there are 4 fluorine atoms:
\[ 6 + (4 \times 1) = 10 \text{ electrons} \]
2. **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{10}{2} = 5 \quad (\text{sp}^3d) \]
3. **Geometry**: With 4 bond pairs and 1 lone pair, SF₄ has a seesaw geometry.

### Step 3: Determine the hybridization and geometry of SF₆
1. **Valence Electrons**: Sulfur (S) has 6 valence electrons, and there are 6 fluorine atoms:
\[ 6 + (6 \times 1) = 12 \text{ electrons} \]
2. **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{12}{2} = 6 \quad (\text{sp}^3d^2) \]
3. **Geometry**: With 6 bond pairs and 0 lone pairs, SF₆ has an octahedral geometry.

### Step 4: Determine the hybridization and geometry of XeF₆
1. **Valence Electrons**: Xenon (Xe) has 8 valence electrons, and there are 6 fluorine atoms:
\[ 8 + (6 \times 1) = 14 \text{ electrons} \]
2. **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{14}{2} = 7 \quad (\text{sp}^3d^3) \]
3. **Geometry**: With 6 bond pairs and 1 lone pair, XeF₆ has a distorted octahedral geometry.

### Summary of Results
- **XeF₄**: Hybridization = sp³d², Geometry = Square Planar (matches with q)
- **SF₄**: Hybridization = sp³d, Geometry = Seesaw (matches with p)
- **SF₆**: Hybridization = sp³d², Geometry = Octahedral (matches with s)
- **XeF₆**: Hybridization = sp³d³, Geometry = Distorted Octahedral (matches with r)

### Final Matching
- A → q (XeF₄)
- B → p (SF₄)
- C → s (SF₆)
- D → r (XeF₆)