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What is the pH of 1MNaPO(4) solution at ...

What is the `pH` of `1MNaPO_(4)` solution at `25^(@)C`?
`PO_(4)^(3-)+H_(2)OhArrHPO_(4)^(2-)+OH^(-),K_(b)=2.4xx10^(-2)`
Assume no hydrolysis of `HPO_(4)^(2-)` ions.

Text Solution

AI Generated Solution

To find the pH of a 1M NaPO₄ solution at 25°C, we need to analyze the hydrolysis of the phosphate ion (PO₄³⁻) in water. The relevant reaction is: \[ \text{PO}_4^{3-} + \text{H}_2\text{O} \rightleftharpoons \text{HPO}_4^{2-} + \text{OH}^- \] Given that the base dissociation constant (Kₐ) for this reaction is: \[ K_b = 2.4 \times 10^{-2} \] ...
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