Complete the following reaction and write the structure of the product formed.
`B_(2)H_(6)underset("High temp.")overset("Excess NH_(3))")to`

Answer

To complete the reaction of diborane (B₂H₆) with excess ammonia (NH₃) at high temperature, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are diborane (B₂H₆) and ammonia (NH₃).

### Step 2: Understand the Reaction Conditions
The reaction is carried out at high temperature and with excess ammonia. This indicates that the reaction will likely lead to the formation of a stable compound.

### Step 3: Determine the Product
When diborane reacts with ammonia under these conditions, it forms a compound known as borazole (B₃N₃H₆), which can also be referred to as borazine.

### Step 4: Write the Chemical Equation
The balanced chemical equation for the reaction can be written as:
\[ B_2H_6 + 3NH_3 \rightarrow B_3N_3H_6 + 3H_2 \]

### Step 5: Draw the Structure of Borazole
Borazole (B₃N₃H₆) has a cyclic structure similar to benzene, with alternating boron and nitrogen atoms. The structure can be represented as follows:

1. Start with a six-membered ring.
2. Alternate boron (B) and nitrogen (N) atoms around the ring.
3. Each boron atom is bonded to one hydrogen atom.
4. The nitrogen atoms are also bonded to one hydrogen atom each.
5. The bonds between boron and nitrogen are single bonds, while the bonds between alternating atoms are double bonds.

The structure can be drawn as:
```
H H
\ /
B = N
/ \
N B
\ /
B = N
/ \
H H
```

### Final Product
The final product of the reaction is borazole (B₃N₃H₆), which has a structure resembling that of benzene but consists of alternating boron and nitrogen atoms.

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