How many of the following are more electronegativity than Boron. `H, Li, Be, C, N, O, F`

Explanation

To determine how many of the given elements are more electronegative than boron, we will follow these steps:

### Step 1: Identify the electronegativity of Boron
Boron (B) has an electronegativity value of approximately 2.04 on the Pauling scale.

### Step 2: List the electronegativity values of the given elements
- Hydrogen (H): 2.20
- Lithium (Li): 0.98
- Beryllium (Be): 1.57
- Carbon (C): 2.55
- Nitrogen (N): 3.04
- Oxygen (O): 3.44
- Fluorine (F): 3.98

### Step 3: Compare each element's electronegativity with that of Boron
- **Hydrogen (H)**: 2.20 > 2.04 (more electronegative)
- **Lithium (Li)**: 0.98 < 2.04 (less electronegative)
- **Beryllium (Be)**: 1.57 < 2.04 (less electronegative)
- **Carbon (C)**: 2.55 > 2.04 (more electronegative)
- **Nitrogen (N)**: 3.04 > 2.04 (more electronegative)
- **Oxygen (O)**: 3.44 > 2.04 (more electronegative)
- **Fluorine (F)**: 3.98 > 2.04 (more electronegative)

### Step 4: Count the elements that are more electronegative than Boron
From the comparison:
- Hydrogen (H)
- Carbon (C)
- Nitrogen (N)
- Oxygen (O)
- Fluorine (F)

Thus, there are **five elements** (H, C, N, O, F) that are more electronegative than Boron.

### Final Answer:
**5 elements are more electronegative than Boron.**

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