Total number of elements which have more ionization energy as compare to their next higher atomic number elements. `Li, be, C, N, O, F, Ne`

Explanation

To solve the question regarding the total number of elements that have more ionization energy compared to their next higher atomic number elements from the given list (Li, Be, C, N, O, F, Ne), we will analyze each element step by step.

### Step-by-Step Solution:

1. **Identify the Elements and Their Atomic Numbers:**
- Lithium (Li) - Atomic Number 3
- Beryllium (Be) - Atomic Number 4
- Carbon (C) - Atomic Number 6
- Nitrogen (N) - Atomic Number 7
- Oxygen (O) - Atomic Number 8
- Fluorine (F) - Atomic Number 9
- Neon (Ne) - Atomic Number 10

2. **Determine the Ionization Energies:**
- **Li (3)**: Ionization energy < Be (4)
- **Be (4)**: Ionization energy > B (5)
- **C (6)**: Ionization energy < N (7)
- **N (7)**: Ionization energy > O (8)
- **O (8)**: Ionization energy < F (9)
- **F (9)**: Ionization energy < Ne (10)

3. **Analyze Each Element:**
- **Lithium (Li)**: Has lower ionization energy than Beryllium (Be).
- **Beryllium (Be)**: Has higher ionization energy than Boron (B).
- **Carbon (C)**: Has lower ionization energy than Nitrogen (N).
- **Nitrogen (N)**: Has higher ionization energy than Oxygen (O).
- **Oxygen (O)**: Has lower ionization energy than Fluorine (F).
- **Fluorine (F)**: Has lower ionization energy than Neon (Ne).
- **Neon (Ne)**: Has higher ionization energy than Sodium (Na).

4. **Count the Elements with Higher Ionization Energy:**
- Beryllium (Be) > Boron (B)
- Nitrogen (N) > Oxygen (O)
- Neon (Ne) > Sodium (Na)

5. **Conclusion:**
- The elements that have higher ionization energy compared to their next higher atomic number elements are Beryllium, Nitrogen, and Neon.
- Therefore, the total number of elements that meet the criteria is **3**.

### Final Answer:
The total number of elements which have more ionization energy compared to their next higher atomic number elements is **3**.