Find the hybridization state of each carbon atoms in following compound?
`CH_(2)=C=CH-CH_(2)-C=C-CH_(2)-NH_(2)`

Answer

To find the hybridization state of each carbon atom in the compound `CH₂=C=CH-CH₂-C=C-CH₂-NH₂`, we can follow these steps:

### Step 1: Draw the Structure
First, we need to visualize the structure of the compound. The compound can be represented as follows:

```
H H H H H H
| | | | | |
H--C=C=C--C--C=C--C--N--H
| | | | |
H H H H H
```

### Step 2: Identify Each Carbon Atom
Label each carbon atom in the structure for clarity:
- C1: CH₂ (first carbon)
- C2: C (double bond with C3)
- C3: C (double bond with C2 and C4)
- C4: CH₂ (single bond with C3 and C5)
- C5: C (double bond with C6)
- C6: C (double bond with C5 and CH₂)
- C7: CH₂ (last carbon)

### Step 3: Count Sigma Bonds
Now, we will count the number of sigma bonds (σ) for each carbon atom:
- **C1 (CH₂)**: 2 (C-H) + 1 (C-C) = 3 σ bonds
- **C2 (C)**: 1 (C-C) + 1 (C=C) = 2 σ bonds
- **C3 (C)**: 1 (C-C) + 1 (C=C) + 1 (C-C) = 3 σ bonds
- **C4 (CH₂)**: 2 (C-H) + 1 (C-C) = 3 σ bonds
- **C5 (C)**: 1 (C-C) + 1 (C=C) = 2 σ bonds
- **C6 (C)**: 1 (C-C) + 1 (C=C) + 1 (C-C) = 3 σ bonds
- **C7 (CH₂)**: 2 (C-H) + 1 (C-C) = 3 σ bonds

### Step 4: Determine Hybridization
Using the number of sigma bonds, we can determine the hybridization:
- **Hybridization Formula**:
- 2 σ bonds = sp
- 3 σ bonds = sp²
- 4 σ bonds = sp³

Now, we can assign hybridization to each carbon:
- **C1**: 3 σ bonds → sp²
- **C2**: 2 σ bonds → sp
- **C3**: 3 σ bonds → sp²
- **C4**: 3 σ bonds → sp²
- **C5**: 2 σ bonds → sp
- **C6**: 3 σ bonds → sp²
- **C7**: 3 σ bonds → sp²

### Summary of Hybridization
- C1: sp²
- C2: sp
- C3: sp²
- C4: sp²
- C5: sp
- C6: sp²
- C7: sp²

### Final Answer
The hybridization states of each carbon atom in the compound `CH₂=C=CH-CH₂-C=C-CH₂-NH₂` are:
- C1: sp²
- C2: sp
- C3: sp²
- C4: sp²
- C5: sp
- C6: sp²
- C7: sp²