The number of structural isomers of for `C_(4)H_(9)Cl` are:

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of structural isomers for the compound C₄H₉Cl, we can follow these steps:

### Step 1: Identify the Base Structure
The molecular formula C₄H₉Cl indicates that we have a four-carbon chain (butane) with one chlorine atom substituting a hydrogen atom.

### Step 2: Draw the Parent Hydrocarbon
The parent hydrocarbon is butane (C₄H₁₀). The structure of butane is:
```
CH₃-CH₂-CH₂-CH₃
```

### Step 3: Consider Substitution of Chlorine
Since we have C₄H₉Cl, we will replace one hydrogen atom in butane with a chlorine atom. This can lead to different structural isomers based on the position of the chlorine atom and the arrangement of the carbon chain.

### Step 4: Identify Possible Isomers
1. **n-Butyl Chloride (1-chlorobutane)**: Chlorine is attached to the first carbon.
```
CH₃-CH₂-CH₂-CH₂Cl
```

2. **Isobutyl Chloride (2-chlorobutane)**: Chlorine is attached to the second carbon.
```
CH₃-CH(CH₃)-CH₂Cl
```

3. **Sec-butyl Chloride (3-chlorobutane)**: Chlorine is attached to the third carbon.
```
CH₃-CH₂-CH(CH₃)-Cl
```

4. **Tertiary Butyl Chloride (tert-butyl chloride)**: Chlorine is attached to the central carbon of a branched structure.
```
(CH₃)₃C-Cl
```

### Step 5: Count the Isomers
From the structures drawn, we can identify the following four structural isomers:
1. n-Butyl chloride
2. Isobutyl chloride
3. Sec-butyl chloride
4. Tertiary butyl chloride

### Conclusion
The total number of structural isomers for C₄H₉Cl is **4**.