Which of the following compound will give smell of `NH_(3)` with conc. `NaOH`.

Options

A. `CH_(3)-CH_(2)-underset(O)underset(||)C-NH_(2)`
B. `CH_(3)-underset(O)underset(||)C-CH_(2)-NH_(2)`
C.
D. `CH_(3)-CH_(2)-underset(O)underset(||)C-OH`

Explanation

To determine which compound will give the smell of ammonia (NH₃) when treated with concentrated sodium hydroxide (NaOH), we need to analyze the behavior of different types of compounds when they react with strong bases.

### Step-by-Step Solution:

1. **Identify the Compounds**: The question mentions several compounds, including an amide, an amine, and possibly others. We need to focus on their structures and functional groups.

2. **Understand the Reaction with NaOH**: When a compound reacts with concentrated NaOH, we need to consider how the functional groups will interact with the base. Specifically, we are looking for a reaction that produces ammonia gas.

3. **Analyze the Amide Reaction**:
- Amides (like propanamide) can undergo hydrolysis in the presence of a strong base.
- The reaction can be represented as:
\[ \text{RCONH}_2 + \text{NaOH} \rightarrow \text{RCOONa} + \text{NH}_3 \]
- Here, the amide is converted into a sodium salt of the corresponding carboxylic acid and ammonia gas is released.

4. **Analyze the Amine Reaction**:
- Amines do not produce ammonia when treated with NaOH. Instead, they may form an ammonium salt but do not release NH₃ gas.

5. **Analyze Other Functional Groups**:
- For carboxylic acids, the reaction with NaOH leads to the formation of a carboxylate salt and water, but no ammonia is produced.
- Other compounds may also not yield ammonia upon reaction with NaOH.

6. **Conclusion**: Based on the analysis, the only compound that produces ammonia gas when treated with concentrated NaOH is an amide. Therefore, the correct answer is the compound that is an amide.

### Final Answer:
The compound that will give the smell of NH₃ with concentrated NaOH is **the amide** (option 1).