On mixing a certain alkane with chlorine...

On mixing a certain alkane with chlorine and irradiating it with UV light, it form only two monochloro alkanes. The alkane could be:

propane

pentane

isopentane

neopentane

Text Solution

Verified by Experts

The correct Answer is:

The numberof monohalogenation products obtained from any alkane depends upon the number of different types of hydrogen it contains. Compound containng only one type of hydrogen gives only one monohalogenation product.
`{:(underset("propane")(CH_(3)CH_(2)CH_(3)),-,underset(("two monohalogenation structural product"))("two types of hydrogen"),),(underset("pentane")(CH_(3)CH_(2)CH_(2)CH_(3)),-,underset(("two monohalogenation structural product"))("three types of hydrogen"),),(underset("isopentane")(CH_(3)-overset(CH_(3))overset(|)(CH)-CH_(2)-CH_(3)),-,"four types of hydrogen" " " ("four monohalogenation structural product"),),(H_(3)C-underset("neopentane")(underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C )-CH_(3)),-,"one types of hydrogen" " " ("one monohalogenation structural product"),):}`
Thus the given alkane should be beopentane.

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An alkane cannot be chlorinated by using which of the following reagents?

`Cl_(2)//hv`

`HCl`

`SO_(2)Cl_(2)`

`t-Bu-O-Cl`

On halogenation, an alkane gives only one monohalogenated product. The alkane may be :

2-methyl butane

2, 2-dimethyl propane

cyclopentane

both (b) and (c)

An alkane (mol. Wt. = 86) on bromination gives only two monobromo derivatives (excluding stereoisomers). The alkane is :

`CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - CH_(2) - CH_(3)`

`CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(2) - CH_(3)`

`CH_(3) - underset(CH_(3))underset(|)(CH) - underset(CH_(3))underset(|)(CH) - CH_(3)`

`CH_(3) - underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C) - CH_(3)`