Home
Class 12
CHEMISTRY
The maximum radial probability in 1s-orb...

The maximum radial probability in `1s`-orbital occures at a distance when : `[r_(0)= "Bohr radius"]`

A

`r=r_(0)`

B

`r=2r_(0)`

C

`r=r_(0)/2`

D

`2 r=r_(0)/2`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the distance at which the maximum radial probability in the 1s orbital occurs, we can follow these steps: ### Step 1: Understand the Concept of Radial Probability The radial probability density for an electron in an atom is given by the function that describes the likelihood of finding an electron at a certain distance from the nucleus. For the 1s orbital, this is influenced by the quantum number \( n \) and the radial wave function. ### Step 2: Identify the Quantum Numbers For the 1s orbital, the principal quantum number \( n = 1 \). The number of nodes in the radial wave function is given by \( n - 1 \). Since \( n = 1 \), the number of nodes is: \[ n - 1 = 1 - 1 = 0 \] This indicates that the 1s orbital has no nodes. ### Step 3: Analyze the Radial Probability Distribution The radial probability distribution for the 1s orbital can be expressed mathematically. The maximum radial probability occurs at a specific distance from the nucleus, which is related to the Bohr radius \( r_0 \). ### Step 4: Relate to the Bohr Radius The Bohr radius \( r_0 \) is a fundamental physical constant that represents the most probable distance of the electron from the nucleus in the hydrogen atom. For the 1s orbital, the maximum radial probability is found at this distance: \[ r = r_0 \] ### Step 5: Conclusion Thus, the maximum radial probability in the 1s orbital occurs at a distance equal to the Bohr radius \( r_0 \). ### Final Answer The maximum radial probability in the 1s orbital occurs at a distance when \( r = r_0 \) (Bohr radius). ---

To determine the distance at which the maximum radial probability in the 1s orbital occurs, we can follow these steps: ### Step 1: Understand the Concept of Radial Probability The radial probability density for an electron in an atom is given by the function that describes the likelihood of finding an electron at a certain distance from the nucleus. For the 1s orbital, this is influenced by the quantum number \( n \) and the radial wave function. ### Step 2: Identify the Quantum Numbers For the 1s orbital, the principal quantum number \( n = 1 \). The number of nodes in the radial wave function is given by \( n - 1 \). Since \( n = 1 \), the number of nodes is: \[ ...
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The variation of radial probability density R^2 (r) as a function of distance r of the electron from the nucleus for 3p orbital: (A)(a) (b) (b) (c) (d)

Radius of 3rd Bohr orbit is

The number of radial nodes in 4s and 3p orbitals are respectively

The first orbital of H is represented by: psi=(1)/(sqrtpi)((1)/(a_(0)))^(3//2)e^(-r//a_(0)) , where a_(0) is Bohr's radius. The probability of finding the electron at a distance r, from the nucleus in the region dV is :

The number of nodes possible in radial probability distribution curve of 3d orbital is

The number of radial nodes of 3s and 2s orbital are respectively:

Assertion (A) : The radial probability of 1s electrons first increases,till it is maximum at 0.53 Å and then decreases to zero Reason (R ) : Bohr's radius for the first is 0.53 Å

The radius of second Bohr’s orbit of Hydrogen atom is:

The radial probability is the probability of finding electron in a small spherical shell around the nucleus at a particular distance r. Hence radial probability is

Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect ? (The Bohr radius is represented by a_(0) ).