Calculate the work done by `0.1` mole of a gas at `27^(@)C` to double its volume at constant pressure `(R = 2 cal mol^(-1)K^(-1))`
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`(V_(1))/(V_(2)) = (T_(1))/(T_(2)) rArr (V)/(2V) = (300)/(T_(2)) rArr T_(2) = 600 rArr Delta T = 300` `W = -P Delta V = nRDelta T` `rArr W = -0.1 xx 2 xx 300 = -60 cal`.
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