Calculate the number of kJ of heat necessary to raise the temperature of 60.0 g of aluminium from `35^(@)C "to" 55^(@)C.` Molar heat capacity of Al is 24 J `mol^(-1) K^(-1)`.
Text Solution
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`q = nC Delta T = ((60)/(27)) xx 24 xx (55-35) = 1066 J = 1.066 kJ`
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