Comment on the following statements:
(a) An exothermic reaction is always thermodynamically spontaneous.
Reaction with `DeltaG lt O` always have an equilibrium constant greater than `1`

Answer

(a) When `DeltaH=-ve "and" TDeltaS`=- ve also `T DeltaS gt DeltaH` then `DeltaG`=+ ve in such case, the reaction will not be spontaneous.
(b) `-DeltaG^(@) =2.303 RT "log"K_(c)`
If `DeltaG_(@)` is negative (not to say that `DeltaG^(@) lt 0`) then `K_(c)` will be +ve and will have value greater than one.

Explanation

When `DeltaH =-ve` and `T DeltaS =-ve `,also `TDeltaS gt DeltaH " then " DeltaG =+ ve` in such case, the reaction will not be spontaneous.
(b) `-DeltaG^(@) =2.303"RT log"K_(c)`
If `DeltaG^(@) ` is negative (not to say that `DeltaG^(@) lt O)` then `K_(c)` will be `+ve` and will have value greather than one.