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The equilibrium constant for a reaction ...

The equilibrium constant for a reaction is 10. What will be the value of `DeltaG^(theta)`?
`R=8.314 JK^(-1)mol^(-1)T=300JK.`

Text Solution

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The correct Answer is:
6
Given : `" "K_("eq") = 10`
`" "T= 300` K
Asked : `DeltaG^(@) =?`
Formula: `" DeltaG^(@) =-2.303` RT log `K_("eq")`
Explanation: `DeltaG^(@)` = Standard Gibb's free energy change
`" "` R= Gas constant (`R=8.314 JK^(-1) mol^(-1))`
`" "` T= Temperature in K
`" " K_("eq")` = equilibrium constant
Substitution & calculation
`" "=-2.3030 xx 8.31 xx 314` log `10` J
`" "=-6 "KJ mol"^(-1)`.
The value of `DeltaG^(@)` is -6 KJ `mol^(-1)`.
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