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In the galvanic cell Cu|Cu^(2+)||Ag^(+)|...

In the galvanic cell `Cu|Cu^(2+)||Ag^(+)|Ag`, the electrons flow from `Cu`- electrode at `Ag`- electrode. Answer the following questions regarding this cell:
(a). Which is the anode?
(b). Which is the cathode?
(c). What happends at anode-reduction or oxidation?
(d). What happens at cathode-oxidation or reduction?
(e). Which electrode loses mass?
(f). Which electrode gais mass?
(g). white the electrode reaction.
(h). Write the cell reaction.
(i). Which metal has greater tendency to loss electron-Cu or Ag?
(J) Which is the more reactive metal Cu or Ag?
(k). What is the function of salt bridge represented by the symbol||?

Text Solution

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The correct Answer is:
(a). Cu.
(b). Ag
(c). Oxidation.
(d). Reduction
(e) Cu.
(f). Ag
(g) anode `CutoCu^(2+)+2e^(-)`, cathode `Ag^(+)e^(-)toAg`
(h). `Cu+2Ag^(+)toCu^(2+)+2Ag` (i). Cu
(j). Cu.
(k). To complete circuit and maintain electrical neutrality in solution.
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Knowledge Check

  • For the galvanic cell, Cu|Cu^(2+)"||"Ag^(+)|Ag . Which of the following observations is not correct ?

    A
    Cu acts as anode and Ag acts as cathode.
    B
    Ag electrode loses mass and Cu electrode gains mass.
    C
    Reaction at anode, `Cu to Cu^(2+) + 2e^-`
    D
    Copper is more reactive than silver .
  • Brine is electrolysed by using inert electrodes. The reaction at anode is

    A
    `Cl^(-)(aq) to 1//2 Cl_2(g) + e^(-) , E_("cell")= 1.36V`
    B
    `2H_2O (l) to O_2(g) + 4H^(+) (aq)^(+) 4e^(-) , E_("cell") = 1.23 V`
    C
    `Na^(+) (aq) + e^(-) to Na(s) , E_("cell") = 2.71V`
    D
    `H^(+)(aq) + e^(-) to 1//2 H_2(g) , E_("cell") = 0.00V`
  • Brine is electrolysed by using inert electrodes. The reaction at anode is

    A
    `Cl^(-)(aq) to 1//2 Cl_2(g) + e^(-) , E_("cell")= 1.36V`
    B
    `2H_2O (l) to O_2(g) + 4H^(+) (aq)^(+) 4e^(-) , E_("cell") = 1.23 V`
    C
    `Na^(+) (aq) + e^(-) to Na(s) , E_("cell") = 2.71V`
    D
    `H^(+)(aq) + e^(-) to 1//2 H_2(g) , E_("cell") = 0.00V`
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