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The electrode with reaction :Cr(2)O(7)^(...

The electrode with reaction `:Cr_(2)O_(7)^(2-)(aq)+14H^(o+)(aq)+6e^(-) rarr 2Cr^(3+)(aq)+7H_(2)O` can be represented as

A

`MnO_(4)^(-)` can be used in aqueous `HCl`

B

`Cr_(2)O_(7)^(2-)` can be used in aqueous `HCl`

C

`MnO_(4)^(-)` can be used in aqueous `H_(2)SO_(4)`

D

`Cr_(2)O_(7)^(2-)` can be used in aqueous `H_(2)SO_(4)`.

Text Solution

Verified by Experts

The correct Answer is:
A
`MnO_(4)^(-)` ion can oxidise both `Fe^(2+)` to `Fe^(3+)` as well as `Cl^(-)` to `Cl_(2)`. So `Fe(NO_(3))_(2)` cannot be estimated quantitatively with `MnO_(4)^(-)` ion in HCl.
`E_(cell)^(@)` for the cell Pt, `Cl_(2)(g)(1atm)|Cl^(-)(aq)||MnO_(4)^(-)(aq)|Mn^(2+)(aq)`. is equal to `(1.51-1.4)=0.11V`
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What type of a battery is lead storage battery? Write the anode and cathode reactions and the overall cell reaction occurring in the operation of a lead storage battery. (b) Calucluate the potential for half-cell containing. 0.10 M K_(2)Cr_(2)O_(7)(aq), 0.20 M Cr^(3+) (aq) and 1.0 xx 10^(-4) M H^(+) (aq) The half -cell reaction is Cr_(2)O_(7)^(2-) (aq) + 4H^(+) (aq) + 6 e^(-) to 2 Cr^(3+) (aq) + 7H_(2)O(l) and the standard electron potential is given as E^(o) = 1.33V .

The cell reaction Cr_2O_7^(2-)(aq)+14H^+(aq)+6Fe^(2+)(aq)to6Fe^(3+)(aq)+2Cr^(3+)(aq)+7H_2O(l) is best represented by:

Knowledge Check

  • Choose correct statements (s) regarding the following reactions. Cr_(2)O_(7)^(2-)(aq)+3SO_(3)^(2-)(aq)+8H^(+) rarr 2Cr^(3+)(aq)+3SO_(4)^(2-)(aq)+4H_(2)O

    A
    `Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+2H_((aq))^(+)rarr 2Cr_((aq))^(3+) rarr 2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+H_(2)O_((l))`
    B
    `2Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+4H_((aq))^(+)rarr 4Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+2H_(2)O_((l))`
    C
    `Cr_(2)O_(7(aq))^(2-)+3SO_(2(g))+14H_((aq))^(+)rarr 2Cr_((aq))^(3+)+3SO_(4(aq))^(2-)+7H_(2)O_((l))`
    D
    `Cr_(2)O_(7(aq))^(2-)+6SO_(2(g))+7H_((aq))^(+)rarr 2Cr_((aq))^(3+)+6SO_(4(aq))^(2-)+7H_(2)O_((l))`

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    In the reaction: Cr_(2)O_(7)^(2-) + 14H^(o+) + 6I^(Ө) rarr2Cr^(3+) + 3H_(2)O + 3I_(2) Which element is reduced?

    For reaction : Cr_(2)O_(7)^(-2)+14H^(+)rarr2Cr^(+3)+7H_(2)O , How many e^(-)s are required

    Cr_(2)O_(7)^(2-)+H^(+)+SO_(3)^(2-) to Cr^(3+)(aq.)+SO_(4)^(2-)

    Cr_(2)O_(7)^(2-)+H^(+)+SO_(3)^(2-) to Cr^(3+)(aq.)+SO_(4)^(2-)

    Consider the reaction : Cr_(2)O_(7)^(2-)+14H^(o+)+6e^(-) rarr 2Cr^(+3)+8H_(2)O What is the quantity of electricity in coulombs needed to reduce 1 mol e of Cr_(2)O_(7)^(2-) ?

    Calculate the potential for half-cell containing 0.10 MK_(2)Cr_(2)O_(7)(aq),0.20M Cr^(3+)(aq) and 1.0xx10^(-4)MH^(+)(aq) . The half-cell reaction is Cr_(2) O_(7)^(2-)(aq) +14H^(+) +6e^(-) to 2Cr^(3+)(aq) +7H_(2)O(l)

    Standard electrode potential data are useful for understanding the suitability of an oxidant in a redox titration. Some half cell reaction and their standard potentials are given below: MnO_(4)^(-)(aq) +8H^(+)(aq) +5e^(-) rarr Mn^(2+)(aq) +4H_(2)O(l) E^(@) = 1.51V Cr_(2)O_(7)^(2-)(aq) +14H^(+) (aq) +6e^(-) rarr 2Cr^(3+)(aq) +7H_(2)O(l), E^(@) = 1.38V Fe^(3+) (aq) +e^(-) rarr Fe^(2+) (aq), E^(@) = 0.77V CI_(2)(g) +2e^(-) rarr 2CI^(-)(aq), E^(@) = 1.40V Identify the only correct statement regarding quantitative estimation of aqueous Fe(NO_(3))_(2)

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