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A catalyst speeds up a chemical reractio...

A catalyst speeds up a chemical reraction by

A

shifting the equilibrium

B

increasing the activation energy

C

initiating the reaction

D

decreasing energy of activation

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AI Generated Solution

The correct Answer is:
To solve the question "A catalyst speeds up a chemical reaction by", we need to understand the role of a catalyst in a chemical reaction. Let's break down the solution step by step: ### Step 1: Define a Catalyst A catalyst is a substance that increases the rate of a chemical reaction without being consumed in the process. This means that it can participate in the reaction but is regenerated at the end. **Hint:** Remember that a catalyst is not consumed in the reaction; it remains unchanged after the reaction. ### Step 2: Understand the Mechanism Catalysts work by providing an alternative reaction pathway that has a lower activation energy compared to the uncatalyzed reaction. Activation energy is the minimum energy required for a reaction to occur. **Hint:** Focus on the concept of activation energy and how it relates to the speed of a reaction. ### Step 3: Compare Activation Energies In a reaction without a catalyst, the activation energy (Ea) is higher. When a catalyst is present, the activation energy (Ea') is lower. This means that less energy is needed for the reactants to convert into products, allowing the reaction to proceed faster. **Hint:** Visualize the energy profile of a reaction with and without a catalyst to see how the activation energies differ. ### Step 4: Analyze the Options Now, we can analyze the provided options: 1. It shifts the equilibrium - **Incorrect**: Catalysts do not affect the position of equilibrium; they only speed up the rate at which equilibrium is reached. 2. It increases the activation energy - **Incorrect**: Catalysts actually decrease the activation energy. 3. Initiating the reaction - **Incorrect**: Catalysts do not initiate reactions; they merely speed them up. 4. It decreases the energy of activation - **Correct**: This is the definition of how a catalyst functions. **Hint:** Eliminate options that do not align with the fundamental properties of catalysts. ### Step 5: Conclusion Based on the analysis, the correct answer to the question is that a catalyst speeds up a chemical reaction by decreasing the energy of activation. **Final Answer:** A catalyst speeds up a chemical reaction by decreasing the energy of activation.
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RESONANCE ENGLISH-CHEMICAL EQUILIBRIUM-Advanced Level Problems (Part-3)(Stage-1)
  1. For the reaction: 4NH(3)(g)+7O(2(g))hArr4NO(2(g))+6H(2)O(g).K(p) is ...

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  2. When K(c)gt1 for a chemical reaction,

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  3. What will be the effect to increased pressure in the following equilib...

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  4. In which reaction will an increase in the volume of the container favo...

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  5. Which of the following changes the value of the equilibrium constant ?

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  6. Consider the equilibrium reaction: 4NH(3((g)))+3O(2((g)))hArr2N(2((g...

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  7. Equilibrium constants K(1) and K(2) for the following equilibria NO(...

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  8. A catalyst speeds up a chemical reraction by

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  9. For the reaction 2HIhArrH(2)(g)+I(2)(g)

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  10. consider the following gaseous equilibrium with equilibrium constant K...

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  11. The equilibrium constant K(c) for the reaction, 2NaHCO(3)(s)hArrNa(2...

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  12. For the following reaction, the value of K change with N(2)(g)+O(2)(...

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  13. For the reaction PCl(3)(g)+Cl(2)(g)rarrPCl(5)(g),K(c) is 26 at 250^(@)...

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  14. At 445^(@)C,K(c) for the following reaction is 0.020. 2HI(g)rarrH(2)...

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  15. A catalyst accelerates a reaction primarily by stablizing the

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  16. The oxidation of SO(2) to SO(3) is an exothermic reaction. The yield o...

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  17. In which of the following reaction K(p) gt K(c) ?

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  18. The K(p)//K(c) ratio for the reaction: 4NH(3)(g)+7O(2)(g)hArr4NO(g)+...

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  19. K(p) for the reaction given below is 1.36 "at" 499K. Which of the fo...

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  20. At 700K, for the reaction 2SO(2)(g)+O(2)(g)hArr2SO(3)(g) the K(p) "is"...

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