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The maximum oxidation state shown by V(Z...

The maximum oxidation state shown by `V(Z=23),Cr(Z=24),Co(Z=27),Sc(Z=21)`, are respectively

A

`+5,+6,+3,+3`

B

`+3,+4,+5,+2`

C

`+5,+3,+2,+1`

D

`+4` in each case.

Text Solution

Verified by Experts

The correct Answer is:
A
1. Electron configuration of V is [Ar] `3d^(3)4s^(2)` and thus maximum 5 electrons participate in bonding.
2. electro configuraiton of Cr is [Ar] `3d^(5)4s^(1)` and thus maximum 6 electrons participate in bonding
3. Electron configuraiton of Co is [Ar] `3d^(7)4s^(2)`. In octahedral splitting in presence of ligands, half filled `t_(2g)^(6)` has higher CFSE and thus +3 oxidation state is most stable.
4. Electron configuraiton of Sc is [Ar] `3d^(1)4s^(2)` and thus maximum 3 electrons participate in bonding.
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