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(i)A powdered substance (A) on treatment...

(i)A powdered substance (A) on treatment with fusion mixture `(Na_2CO_3+KNO_3)` gives a green coloured compound (B).
(ii)The solution of (B) in boiling water on acidification with dilute `H_2SO_4` gives a pink coloured compound ( C).
(iii)The aqueous solution of (A) on treatment with excess of NaOH and Bromine water gives a compound (D)
(iv)A solution of (D) in conc. `HNO_3` on treatment with `PbO_2` at boiling temperature produced a compound (E) which was of the same colour at that of (C ).
Sum of oxidation number of central atom of A,B,C,D & E is:

A

It oxidises ammonia to nitrogen dioxide in neutral medium

B

it's pink colour is due to d-d transition

C

it can be oxidised by ozone.

D

it is obtained by alkaline fusion of pyrolusite followed by electrolytic oxidation.

Text Solution

Verified by Experts

The correct Answer is:
D
A. `2MnO_(4)^(-)+2NH_(3)to2MnO_(2)+N_(2)+2H_(2)O`
B. It is due to charge transfer from `O^2-` to empty d-orbital of Mn(VII)
C. `MnO_(4)^(-)` is in highest oxidation state i.e., +VII and thus can not be oxidised further.
D. `MnO_(2)+OHtoMnO_(2)^(2-)overset([e^(-)])toMnO_(4)^(-)`
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