A compound has cubical unit cell in which X atom are present at 6 corner, Y atom are at remaining corner & only at those face centres which are not opposite to each other & Z atoms are present at remaining face centre & body centre then find.
(i) Formula of compound (ii) Density if edge length `= 2 Å`
Given: Atomic mass of X = 40 amu, Y = 60 amu, Z = 80 amu

Explanation

To solve the problem step by step, we will find the formula of the compound based on the positions of the atoms in the unit cell and then calculate the density using the given edge length and atomic masses.

### Step 1: Determine the number of atoms in the unit cell

1. **X atoms**: Present at 6 corners.
- Contribution from X = \(6 \times \frac{1}{8} = \frac{6}{8} = \frac{3}{4}\)

2. **Y atoms**: Present at the remaining corners and face centers which are not opposite to each other.
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