Total number of ions in 17.1 g Al2(SO4)3...

Total number of ions in 17.1 g `Al_2(SO_4)_3` is `[N_A=6xx10^23]`

A

`1.5xx10^23`

B

`4.5xx10^23`

C

`3xx10^23`

D

`6xx10^22`

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