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Metal carbonyls have the metal ions in z...

Metal carbonyls have the metal ions in zero or unusually lower oxidation states. This is because :

A

carbonyl ligands is reducing in nature.

B

carbonyl is a highly electron rich ligands.

C

carbonyl is a strongly o-bonding ligand.

D

carbonyl is a strongly p-acidic ligand.

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The correct Answer is:
To answer the question, "Why do metal carbonyls have the metal ions in zero or unusually lower oxidation states?", we can break down the explanation into several key steps: ### Step-by-Step Solution: 1. **Understanding Metal Carbonyls**: - Metal carbonyls are coordination compounds where a metal is bonded to carbon monoxide (CO) ligands. 2. **Nature of CO as a Ligand**: - Carbon monoxide (CO) acts as a ligand that can form coordinate bonds with metal ions. It is classified as a **pi-acceptor ligand**. 3. **Oxidation States of Metals in Carbonyls**: - In metal carbonyl complexes, the metal typically exhibits a zero or low oxidation state. This is crucial for the stability of the complex. 4. **Back Bonding Concept**: - The reason for the low oxidation state is due to **back bonding**. In this process, the metal donates electron density from its d-orbitals to the empty pi* (pi star) antibonding orbitals of the CO ligand. 5. **Electron Rich Metals**: - For effective back bonding to occur, the metal must be electron-rich. This condition is met when the metal is in a low or zero oxidation state, allowing it to donate electrons easily. 6. **Strengthening of Metal-CO Bond**: - The back bonding enhances the strength of the metal-CO bond, making the overall complex more stable. It also leads to an increase in the bond length of the CO bond due to the nature of the bonding interaction. 7. **Conclusion**: - Therefore, the presence of CO as a pi-acceptor ligand necessitates that the metal be in a low or zero oxidation state to facilitate back bonding, which stabilizes the metal carbonyl complex. ### Final Answer: Metal carbonyls have the metal ions in zero or unusually lower oxidation states because carbon monoxide (CO) is a pi-acceptor ligand that requires the metal to be electron-rich. This condition is satisfied when the metal is in a low or zero oxidation state, allowing for effective back bonding, which strengthens the metal-CO bond. ---
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RESONANCE ENGLISH-COORDINATION COMPOUNDS-Additional Problem for Self Practice (APSP) Part-II
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