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X gm of metal gave Y gm of its oxide, so...

X gm of metal gave Y gm of its oxide, so equivalent mass of metal is :

A

`(X-Y)/(Y)xx8`

B

`(x)/((y-x))xx8`

C

`(x)/(y)xx8`

D

`(x+y)/(x)xx8`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equivalent mass of the metal given that X grams of metal produced Y grams of its oxide, we can follow these steps: ### Step 1: Understand the relationship between metal, its oxide, and oxygen. The metal reacts with oxygen to form its oxide. Therefore, if we have X grams of metal oxide, we can express the mass of the metal and the mass of oxygen in the oxide. ### Step 2: Calculate the mass of the metal. The mass of the metal can be calculated as: \[ \text{Mass of metal} = \text{Mass of metal oxide} - \text{Mass of oxygen} \] Thus, we have: \[ \text{Mass of metal} = X - Y \text{ grams} \] ### Step 3: Use the equivalent weight relationship. According to the oxide method, the relationship between the weights can be expressed as: \[ \frac{\text{Weight of metal}}{\text{Equivalent weight of metal}} = \frac{\text{Weight of oxygen}}{\text{Equivalent weight of oxygen}} \] ### Step 4: Rearrange the equation to find the equivalent weight of the metal. From the above equation, we can rearrange it to find the equivalent weight of the metal: \[ \text{Equivalent weight of metal} = \frac{\text{Weight of metal} \times \text{Equivalent weight of oxygen}}{\text{Weight of oxygen}} \] ### Step 5: Substitute the known values. We know: - Weight of metal = \( X - Y \) grams - Equivalent weight of oxygen = 8 grams (since the equivalent weight of oxygen is 8 g/mol) - Weight of oxygen = Y grams Substituting these values into the equation gives: \[ \text{Equivalent weight of metal} = \frac{(X - Y) \times 8}{Y} \] ### Step 6: Final expression for equivalent mass of the metal. Thus, the equivalent mass of the metal can be expressed as: \[ \text{Equivalent mass of metal} = \frac{8(X - Y)}{Y} \] ### Conclusion The equivalent mass of the metal is given by the formula: \[ \text{Equivalent mass of metal} = \frac{8(X - Y)}{Y} \] ---
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RESONANCE ENGLISH-EQUIVALENT CONCEPT & TITRATIONS-Exercise -1 (Part-II)
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