Home
Class 12
CHEMISTRY
In basic medium, I^(-) is oxidised by Mn...

In basic medium, `I^(-)` is oxidised by `MnO_(4)^(-)` . In this process, `I^(-)` changes to :

A

`IO_(3)^(-)`

B

`I_(2)`

C

`IO_(4)^(-)`

D

`IO^(-)`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -3 (Part-II)|7 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -3 (JEE(MAIN) Online problems)|10 Videos
  • EQUIVALENT CONCEPT & TITRATIONS

    RESONANCE ENGLISH|Exercise Exercise -2 (Part-IV)|9 Videos
  • ELECTROCHEMISRY

    RESONANCE ENGLISH|Exercise Advanced Level Problems|88 Videos
  • FUNDAMENTAL CONCEPT

    RESONANCE ENGLISH|Exercise ORGANIC CHEMISTRY(Fundamental Concept )|40 Videos

Similar Questions

Explore conceptually related problems

In dilute aqueous H_(2)SO_(4) the complete diaquadioxalatoferrate (II) is oxidised by MnO_(4)^(-) . For the reaction, the ratio of the rate of change of [H^(+)] to the rate of change of [MnO_(4)^(-)] is

Which of the following is not oxidised by MnO_(2) ?

In acidic medium " MnO"_(4)^(-) is an oxidising agent as " MnO"_(4)^(-) +8H^(+)+5e^(-) rarr Mn^(2+)+4H_(2) O . If H^(+) concentration is doubled, electrode potential of the half-cell " MnO"_(4)^(-)// " Mn"^(2+), Pt will :

In acid medium, MnO_(4)^(c-) is an oxidizing agent. MnO_(4)^(c-)+8H^(o+)+5e^(-) rarr Mn^(2+)+4H_(2)O If H^(o+) ion concentration is doubled, electrode potential of the half cell MnO_(4)^(c-), Mn^(2+)|Pt will

In acid medium, MnO_(4)^(c-) is an oxidizing agent. MnO_(4)^(c-)+8H^(o+)+5e^(-) rarr Mn^(2+)+4H_(2)O If H^(o+) ion concentration is doubled, electrode potential of the half cell MnO_(4)^(c-), Mn^(2+)|Pt will

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is:

In a titration, H_(2)O_(2) is oxidised to O_(2) by MnO_(4)^(-) . 24 mL of 0.1M H_(2)O_(2) requires 16 mL of 0.1M MnO_(4)^(-) solution. Hence MnO_(4)^(-) changes to :

In dilute alkaline solution, MnO_(4)^(-) changes to:

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) is :