Identify A and B In following reaction, `H_2SO_4 + HBr to A + B + H_2O `

Options

A. (A) `Br_2, SO_3`
B. (B) `Br_2, S`
C. (C) `BrO_3^(-) , SO_3`
D. (D) `Br_2 , SO_2`

Answer

To solve the reaction \( H_2SO_4 + HBr \rightarrow A + B + H_2O \), we need to identify the products A and B formed when sulfuric acid reacts with hydrogen bromide.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the reaction are sulfuric acid (\( H_2SO_4 \)) and hydrogen bromide (\( HBr \)).

2. **Determine the Nature of the Reactants**:
- Sulfuric acid (\( H_2SO_4 \)) is known to act as an oxidizing agent.
- Hydrogen bromide (\( HBr \)) acts as a reducing agent.

3. **Predict the Reaction**:
In the reaction, the reducing agent (HBr) will be oxidized, and the oxidizing agent (H2SO4) will be reduced.

4. **Oxidation of Hydrogen Bromide**:
When \( HBr \) is oxidized, it forms bromine (\( Br_2 \)).

5. **Reduction of Sulfuric Acid**:
When \( H_2SO_4 \) is reduced, it typically forms sulfur dioxide (\( SO_2 \)).

6. **Write the Products**:
Therefore, the products of the reaction are:
- Product A: \( Br_2 \) (bromine)
- Product B: \( SO_2 \) (sulfur dioxide)

7. **Complete the Reaction**:
The balanced reaction can be summarized as:
\[ H_2SO_4 + 2 HBr \rightarrow Br_2 + SO_2 + 2 H_2O \]

### Conclusion:
Thus, the final answer is:
- A = \( Br_2 \)
- B = \( SO_2 \)

The correct option for this question is \( Br_2 \) and \( SO_2 \).