How many geometrical isomers are possible for the given compound?
Ph-CH=CH-CH=CH-COOH

Options

A. 2
B. 4
C. 6
D. 8

Answer

To determine the number of geometrical isomers for the compound Ph-CH=CH-CH=CH-COOH, we will follow these steps:

### Step 1: Identify the Structure
The compound can be represented as follows:
- Ph-CH=CH-CH=CH-COOH
This indicates a phenyl group (Ph) attached to a chain with two double bonds and a carboxylic acid (COOH) at the end.

### Step 2: Analyze the Double Bonds
The compound has two double bonds (C=C). Each double bond can potentially give rise to geometrical isomers (cis and trans) depending on the substituents attached to the carbons involved in the double bonds.

### Step 3: Determine Possible Isomers
1. **First Double Bond (C1=C2)**:
- If both substituents (H) are on the same side, it is a cis isomer.
- If the substituents are on opposite sides, it is a trans isomer.

2. **Second Double Bond (C3=C4)**:
- Similarly, if both substituents (H) are on the same side, it is a cis isomer.
- If the substituents are on opposite sides, it is a trans isomer.

### Step 4: Count the Combinations
- For the first double bond (C1=C2), we can have:
- Cis (H and Ph on the same side)
- Trans (H and Ph on opposite sides)

- For the second double bond (C3=C4), we can also have:
- Cis (H and COOH on the same side)
- Trans (H and COOH on opposite sides)

### Step 5: Combine the Isomers
Now we can combine the configurations of both double bonds:
1. **Cis (C1=C2) and Cis (C3=C4)**
2. **Cis (C1=C2) and Trans (C3=C4)**
3. **Trans (C1=C2) and Cis (C3=C4)**
4. **Trans (C1=C2) and Trans (C3=C4)**

Thus, we can conclude that there are a total of **4 geometrical isomers** possible for the compound Ph-CH=CH-CH=CH-COOH.

### Final Answer
The total number of geometrical isomers for the given compound is **4**.

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