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C(6)H(12)O(2)(X) overset(H(3)O^(+))toC(2...

`C_(6)H_(12)O_(2)(X) overset(H_(3)O^(+))toC_(2)H_(5)CO_(2)H+C_(3)H_(7)OH`, X is

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To solve the question, we need to determine the structure of compound X (C₆H₁₂O₂) that reacts with H₃O⁺ to yield C₂H₅CO₂H (propanoic acid) and C₃H₇OH (propanol). ### Step-by-Step Solution: 1. **Identify the Reaction Type**: - The reaction involves the formation of an acid and an alcohol from a compound (X) when treated with H₃O⁺. This suggests that X is likely an ester, as esters hydrolyze to produce carboxylic acids and alcohols in the presence of an acid catalyst. **Hint**: Look for functional groups that can yield an acid and an alcohol upon hydrolysis. 2. **Write the General Structure of an Ester**: - An ester has the general structure RCOOR', where R and R' are hydrocarbon chains. In this case, we need to find R and R' such that the total number of carbons is 6 (C₆H₁₂O₂). **Hint**: Remember that the total number of carbon atoms in the ester should equal the sum of the carbon atoms in the products. 3. **Analyze the Products**: - The products are C₂H₅CO₂H (propanoic acid) which has 3 carbons and C₃H₇OH (propanol) which has 3 carbons. Therefore, the total number of carbons in the products is 6, which matches the formula of X. **Hint**: Count the number of carbon atoms in the products to confirm the structure of the ester. 4. **Construct the Ester Structure**: - Since propanoic acid (C₂H₅CO₂H) has a structure of C₂H₅C(=O)OH, we can deduce that the ester must have the propanoic acid part and the alcohol part (propanol, C₃H₇OH). - Therefore, the ester can be constructed as C₂H₅C(=O)O(C₃H₇). **Hint**: Combine the components of the acid and alcohol to form the ester. 5. **Final Structure of X**: - The final structure of X can be represented as: \[ C₂H₅C(=O)O(C₃H₇) \] - This can also be written as: \[ C₆H₁₂O₂ \] - Thus, the compound X is ethyl propanoate (C₂H₅COOC₃H₇). **Hint**: Ensure the final structure matches the molecular formula given in the question. ### Conclusion: The structure of compound X is ethyl propanoate, which can be represented as: \[ \text{X} = C₂H₅C(=O)O(C₃H₇) \]

To solve the question, we need to determine the structure of compound X (C₆H₁₂O₂) that reacts with H₃O⁺ to yield C₂H₅CO₂H (propanoic acid) and C₃H₇OH (propanol). ### Step-by-Step Solution: 1. **Identify the Reaction Type**: - The reaction involves the formation of an acid and an alcohol from a compound (X) when treated with H₃O⁺. This suggests that X is likely an ester, as esters hydrolyze to produce carboxylic acids and alcohols in the presence of an acid catalyst. **Hint**: Look for functional groups that can yield an acid and an alcohol upon hydrolysis. ...
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RESONANCE ENGLISH-CARBONYL COMPOUNDS (ALDEHYDES & KETONES ) & CARBOXYLIC ACID -Part -III
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