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If y=e^(x), then (d^(2)y)/(dx^(2)) = e^(...

If `y=e^(x)`, then `(d^(2)y)/(dx^(2)) = e^(x)`.

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To prove that if \( y = e^x \), then \( \frac{d^2y}{dx^2} = e^x \), we will follow these steps: ### Step 1: Differentiate \( y \) with respect to \( x \) Given: \[ y = e^x \] We need to find the first derivative \( \frac{dy}{dx} \). Using the differentiation rule for the exponential function: \[ \frac{dy}{dx} = e^x \] ### Step 2: Differentiate \( \frac{dy}{dx} \) to find \( \frac{d^2y}{dx^2} \) Now, we need to find the second derivative \( \frac{d^2y}{dx^2} \), which is the derivative of \( \frac{dy}{dx} \): \[ \frac{d^2y}{dx^2} = \frac{d}{dx} \left( \frac{dy}{dx} \right) = \frac{d}{dx} (e^x) \] Again, using the differentiation rule for the exponential function: \[ \frac{d^2y}{dx^2} = e^x \] ### Conclusion We have shown that: \[ \frac{d^2y}{dx^2} = e^x \] Thus, the statement is proven to be true. ---
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Knowledge Check

  • If y = e^(x) sin x then (d^(2)y)/(dx^(2)) =

    A
    `2e^(x) ` sin x
    B
    `2e^(x) ` ( sin x - cos x )
    C
    `2e^(x) (cos x - sin ) `
    D
    `2e^(x) cos x`
  • If y=e^(2x) , then (d^(2)y)/(dx^(2)).(d^(2)x)/(dy^(2)) is equal to

    A
    `e^(-2x)`
    B
    `-2e^(-2x)`
    C
    `2e^(-2x)`
    D
    1
  • If y=e^(nx) , then ((d^(2)y)/(dx^(2)))(d^(2)x)/(dy^(2)) is equal to

    A
    `ne^(nx)`
    B
    `ne^(-nx)`
    C
    1
    D
    `-ne^(-nx)`
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