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The reaction 2X to B is a zeroth order ...

The reaction `2X to B` is a zeroth order reaction .If the initial concention of X is 0.2 M, the half-life is 6 h. When the initial concetration of X is 0.5 M, the time required to reach its final concetration of 0.2 M will be :

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To solve the problem, we need to determine the time required for the concentration of X to decrease from 0.5 M to 0.2 M in a zeroth-order reaction. Here are the steps to derive the solution: ### Step 1: Understand the zeroth-order reaction In a zeroth-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. The rate can be expressed as: \[ \text{Rate} = k \] where \( k \) is the rate constant. ### Step 2: Use the half-life formula for zeroth-order reactions The half-life (\( t_{1/2} \)) for a zeroth-order reaction is given by: \[ t_{1/2} = \frac{[A]_0}{2k} \] where \([A]_0\) is the initial concentration of the reactant. Given that the half-life is 6 hours when the initial concentration of X is 0.2 M, we can use this information to find the rate constant \( k \). ### Step 3: Calculate the rate constant \( k \) Substituting the known values into the half-life formula: \[ 6 = \frac{0.2}{2k} \] Rearranging gives: \[ 2k = \frac{0.2}{6} \] \[ k = \frac{0.2}{12} = \frac{1}{60} \, \text{M/h} \] ### Step 4: Determine the change in concentration Next, we need to find the time required for the concentration of X to decrease from 0.5 M to 0.2 M. The change in concentration (\( \Delta [X] \)) is: \[ \Delta [X] = [X]_0 - [X]_f = 0.5 \, \text{M} - 0.2 \, \text{M} = 0.3 \, \text{M} \] ### Step 5: Use the zeroth-order kinetics equation For a zeroth-order reaction, the change in concentration over time can be expressed as: \[ \Delta [X] = k \cdot t \] Substituting the values we have: \[ 0.3 = \left(\frac{1}{60}\right) \cdot t \] ### Step 6: Solve for time \( t \) Rearranging the equation to solve for \( t \): \[ t = 0.3 \cdot 60 \] \[ t = 18 \, \text{hours} \] ### Conclusion The time required to reach the final concentration of 0.2 M from an initial concentration of 0.5 M is **18 hours**. ---

To solve the problem, we need to determine the time required for the concentration of X to decrease from 0.5 M to 0.2 M in a zeroth-order reaction. Here are the steps to derive the solution: ### Step 1: Understand the zeroth-order reaction In a zeroth-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. The rate can be expressed as: \[ \text{Rate} = k \] where \( k \) is the rate constant. ### Step 2: Use the half-life formula for zeroth-order reactions ...
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Knowledge Check

  • The reaction X to Product follows first order kinetics. In 40 minutes the concentration of X changes from 0.1 M to 0.025 M. Then the rate of reaction when concentration of X is 0.01 M will be

    A
    `1.73 xx 10^(-4) min""^(-1)`
    B
    `3.47 xx 10^(-5) M min""^(-1)`
    C
    `3.47 xx 10^(-4) M min""^(-1)`
    D
    `1.73 xx 10^(-5) M min""^(-1)`
  • The reaction X to Product follows first order kinetics. In 40 minutes the concentration of X changes from 0.1 M to 0.025 M. Then the rate of reaction when concentration of X is 0.01 M will be

    A
    `1.73 xx 10^(-4) min""^(-1)`
    B
    `3.47 xx 10^(-5) M min""^(-1)`
    C
    `3.47 xx 10^(-4) M min""^(-1)`
    D
    `1.73 xx 10^(-5) M min""^(-1)`
  • The reaction X to Product follows first order kinetics. In 40 minutes the concentration of X changes from 0.1 M to 0.025 M. Then the rate of reaction when concentration of X is 0.01 M will be

    A
    `1.73 xx 10^(-4) min""^(-1)`
    B
    `3.47 xx 10^(-5) M min""^(-1)`
    C
    `3.47 xx 10^(-4) M min""^(-1)`
    D
    `1.73 xx 10^(-5) M min""^(-1)`
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