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The sum of number of valence electrons a...

The sum of number of valence electrons and valency of an element with atomic number 15 is_____.

A

8

B

6

C

5

D

10

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the sum of the number of valence electrons and the valency of the element with atomic number 15, which is phosphorus (P). Here's a step-by-step solution: ### Step 1: Identify the Element The element with atomic number 15 is phosphorus (P). ### Step 2: Write the Electronic Configuration Phosphorus has 15 electrons. The electronic configuration can be written as: - 1s² 2s² 2p⁶ 3s² 3p³ ### Step 3: Determine the Number of Valence Electrons The valence electrons are the electrons in the outermost shell. For phosphorus, the outermost shell is the third shell (n=3), which contains: - 3s² (2 electrons) - 3p³ (3 electrons) Adding these together gives: - Total valence electrons = 2 (from 3s) + 3 (from 3p) = 5 valence electrons. ### Step 4: Determine the Valency Valency is the combining capacity of an element. For phosphorus, we look at the number of unpaired electrons in the valence shell: - In the 3p orbital, there are 3 unpaired electrons. Phosphorus can form three bonds by using these unpaired electrons, so its valency is 3. ### Step 5: Calculate the Sum Now we need to find the sum of the number of valence electrons and the valency: - Sum = Number of valence electrons + Valency - Sum = 5 (valence electrons) + 3 (valency) = 8. ### Final Answer The sum of the number of valence electrons and valency of the element with atomic number 15 is **8**. ---

To solve the problem, we need to find the sum of the number of valence electrons and the valency of the element with atomic number 15, which is phosphorus (P). Here's a step-by-step solution: ### Step 1: Identify the Element The element with atomic number 15 is phosphorus (P). ### Step 2: Write the Electronic Configuration Phosphorus has 15 electrons. The electronic configuration can be written as: - 1s² 2s² 2p⁶ 3s² 3p³ ...
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