Chlorine reacts with hot and conc.` Ba (OH)_(2)` and produces compound X, `BaCl _(2)` and water. X further reacts with `H _(2) SO_(4)` to give Y and `BaSO_(4).` The average bond order between Cl and O atoms in any one of Y is `"_______."`

Explanation

To solve the problem step by step, we will analyze the reactions and calculate the average bond order between chlorine (Cl) and oxygen (O) in the compound Y.

### Step 1: Identify the Reaction of Chlorine with Barium Hydroxide
Chlorine reacts with hot and concentrated barium hydroxide (Ba(OH)₂). The reaction produces:
- Compound X: Barium chlorate, \( \text{Ba(ClO}_3\text{)}_2 \)
- Barium chloride, \( \text{BaCl}_2 \)
- Water, \( \text{H}_2\text{O} \)

**Equation:**
\[ \text{Cl}_2 + \text{Ba(OH)}_2 \rightarrow \text{Ba(ClO}_3\text{)}_2 + \text{BaCl}_2 + \text{H}_2\text{O} \]

**Hint:** Remember that chlorine can form chlorates when reacting with hydroxides.

### Step 2: Reaction of Compound X with Sulfuric Acid
Next, compound X (barium chlorate) reacts with sulfuric acid (H₂SO₄) to produce:
- Compound Y: Chloric acid, \( \text{HClO}_3 \)
- Barium sulfate, \( \text{BaSO}_4 \)

**Equation:**
\[ \text{Ba(ClO}_3\text{)}_2 + \text{H}_2\text{SO}_4 \rightarrow 2\text{HClO}_3 + \text{BaSO}_4 \]

**Hint:** Identify the products formed when an acid reacts with a salt.

### Step 3: Determine the Structure of Compound Y
Compound Y is chloric acid, \( \text{HClO}_3 \). To analyze the bond order, we need to draw its Lewis structure.

1. Chlorine (Cl) is the central atom.
2. It is bonded to three oxygen atoms, one of which has a double bond.
3. The structure can be represented as:
- One Cl=O double bond
- Two Cl-O single bonds

**Hint:** Use the octet rule to determine how many bonds each atom forms.

### Step 4: Resonance Structures of \( \text{ClO}_3^- \)
The chlorate ion \( \text{ClO}_3^- \) has resonance structures. The resonance structures can be drawn as follows:
1. One structure with a double bond between Cl and one O, and single bonds with the other two O atoms.
2. The double bond can shift among the three O atoms, leading to three resonance forms.

**Hint:** Remember that resonance structures help in distributing the electron density across the molecule.

### Step 5: Calculate the Average Bond Order
To find the average bond order between Cl and O in \( \text{ClO}_3^- \):
1. Count the total number of bonds between Cl and O in all resonance structures.
- Each structure has 3 bonds (1 double bond + 2 single bonds).
- There are 3 resonance structures.

**Total bonds = 3 bonds × 3 structures = 9 bonds**

2. Average bond order is calculated as:
\[ \text{Average bond order} = \frac{\text{Total number of bonds}}{\text{Number of resonance structures}} = \frac{9}{3} = 3 \]

However, since we have one double bond and two single bonds, we need to consider the effective bond order:
- Each double bond contributes 2, and each single bond contributes 1.
- Therefore, the effective bond order is \( \frac{2 + 1 + 1}{3} = \frac{4}{3} \).

**Final Calculation:**
The average bond order between Cl and O in \( \text{ClO}_3^- \) is approximately \( 1.66 \).

### Final Answer
The average bond order between Cl and O atoms in any one of Y is **1.66**.