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The dipole moments of NH3, NF3 and H2O a...

The dipole moments of `NH_3, NF_3` and `H_2O` are in the order.

A

`NH_3ltNF_3ltH_2O`

B

`NH_3ltNF_3=H_2O`

C

`NF_3ltNH_3ltH_2O`

D

`NF_3ltH_2OltNH_3`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the order of dipole moments for the molecules NH₃ (ammonia), NF₃ (nitrogen trifluoride), and H₂O (water), we need to analyze the molecular geometry and electronegativity of the atoms involved. ### Step 1: Analyze the molecular structures - **NH₃ (Ammonia)**: The nitrogen atom is at the center with three hydrogen atoms bonded to it. The molecule has a trigonal pyramidal shape due to the presence of a lone pair on nitrogen. The dipole moments from the N-H bonds do not cancel out, resulting in a net dipole moment directed towards the nitrogen. - **NF₃ (Nitrogen Trifluoride)**: Similar to NH₃, NF₃ also has a trigonal pyramidal shape. However, the electronegativity of fluorine is higher than that of nitrogen, which means the dipole moments of the N-F bonds point towards the fluorine atoms. The dipole moments in NF₃ tend to cancel out more than in NH₃, leading to a smaller net dipole moment. - **H₂O (Water)**: Water has a bent molecular shape due to two lone pairs on the oxygen atom. The O-H bonds are highly polar due to the high electronegativity of oxygen, and the dipole moments do not cancel out. This results in a significant net dipole moment directed towards the oxygen. ### Step 2: Compare the dipole moments - **NH₃** has a significant dipole moment due to the polar N-H bonds and the geometry that does not allow for cancellation. - **H₂O** has an even larger dipole moment because of the bent shape and the high electronegativity of oxygen. - **NF₃** has the smallest dipole moment because the dipole moments of the N-F bonds largely cancel each other out. ### Conclusion Based on the analysis: - The order of dipole moments is: **H₂O > NH₃ > NF₃**. ### Final Answer The correct order of dipole moments is **H₂O > NH₃ > NF₃**. ---

To determine the order of dipole moments for the molecules NH₃ (ammonia), NF₃ (nitrogen trifluoride), and H₂O (water), we need to analyze the molecular geometry and electronegativity of the atoms involved. ### Step 1: Analyze the molecular structures - **NH₃ (Ammonia)**: The nitrogen atom is at the center with three hydrogen atoms bonded to it. The molecule has a trigonal pyramidal shape due to the presence of a lone pair on nitrogen. The dipole moments from the N-H bonds do not cancel out, resulting in a net dipole moment directed towards the nitrogen. - **NF₃ (Nitrogen Trifluoride)**: Similar to NH₃, NF₃ also has a trigonal pyramidal shape. However, the electronegativity of fluorine is higher than that of nitrogen, which means the dipole moments of the N-F bonds point towards the fluorine atoms. The dipole moments in NF₃ tend to cancel out more than in NH₃, leading to a smaller net dipole moment. - **H₂O (Water)**: Water has a bent molecular shape due to two lone pairs on the oxygen atom. The O-H bonds are highly polar due to the high electronegativity of oxygen, and the dipole moments do not cancel out. This results in a significant net dipole moment directed towards the oxygen. ...
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The dipole moments of CCl _ 4, CHCl _ 3 and CH _ 4 are in the order :

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Knowledge Check

  • The dipole moments of halo compounds are in the order

    A
    `CHCl3 gt "CCl"_4 gt CHCl_2 gt "cis" - CHCI = CHCI`
    B
    `"cis" gt CHCl = CHCl gt CHCl_3 gt CH_2Clgt"CCl"_4`
    C
    `"cis" - CHCI = CHCI gt CH_2Cl_2 gt CHCl_3 gt` CCl
    D
    `CHCl_(3) gt CHCl_(2)gt " cis" - CHCl = CHCl gt "CCl"_4`
  • The dipoles moment of NF_(3) is less than NH_(3) because

    A
    `4.90 xx 10^(-30) C m and 0.80 xx 10^(-30) C m`
    B
    `0.80 xx 10^(-30) C m and 4.90 xx 10^(-30) C m`
    C
    `4.90 xx 10^(-30) C m and 4.90 xx 10^(-30) C m`
    D
    `0.80 xx 10^(-30) C m and 0.80 xx 10^(-30) C m`
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