A certain day absorbs lights of `lamda=400` nm and then fluorescence light of wavelength `500` mn. Assuming that under given condition `40%` of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta obserbed to number of quanta emitted out.

Answer

2

Explanation

Given `40%` of the absorbed energy is reemitted. Let `n_(1)` be the number of quanta absorbed and `n_(2)` be the number of quanta emitted.
`rArr" "n_(1)=(hc)/(lambda_(1))xx(40)/(100)=(n_(2)hc)/(lambda_(2))" "rArr" "(n_(1))/(lambda_(1))xx0.4=(n_(2))/(lambda_(2))" "rArr" "(n_(1))/(n_(2))=(lambda_(1))/(lambda_(2))xx(10)/(4)=(400)/(500)xx(10)/(4)=2`