Home
Class 12
CHEMISTRY
A certain day absorbs lights of lamda=40...

A certain day absorbs lights of `lamda=400` nm and then fluorescence light of wavelength `500` mn. Assuming that under given condition `40%` of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta obserbed to number of quanta emitted out.

Text Solution

Verified by Experts

The correct Answer is:
2
Given `40%` of the absorbed energy is reemitted. Let `n_(1)` be the number of quanta absorbed and `n_(2)` be the number of quanta emitted.
`rArr" "n_(1)=(hc)/(lambda_(1))xx(40)/(100)=(n_(2)hc)/(lambda_(2))" "rArr" "(n_(1))/(lambda_(1))xx0.4=(n_(2))/(lambda_(2))" "rArr" "(n_(1))/(n_(2))=(lambda_(1))/(lambda_(2))xx(10)/(4)=(400)/(500)xx(10)/(4)=2`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    VMC MODULES ENGLISH|Exercise JEE Main (Archive)|39 Videos

  • ATOMIC STRUCTURE

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive )|67 Videos

  • ATOMIC STRUCTURE

    VMC MODULES ENGLISH|Exercise LEVEL - 2|50 Videos

  • AMINES

    VMC MODULES ENGLISH|Exercise IN CHAPTER EXERCISE H|10 Videos

  • CHEMICAL BONDING & CHEMICAL STRUCTURE

    VMC MODULES ENGLISH|Exercise IMPECCABLE|50 Videos

Similar Questions

Explore conceptually related problems

A dye obsorbs light of lambda = 4530 Å and then flaorescences light of 5000Å .Assuming that uinder given condition 47% of the obserbed energy is re-emited out so flaurescence , calculate the ratio of quants emitted out to the number of quanta obserbed

A certain dye absorbs light of cerain wavelength and then fluorescence light of wavelength 5000 Å.Assuming that under given conditions , 50% of the absorbed energy is re-emitted out as fluorescence and the ratio of number of quanta emitted out to the number of quanta absorbed is 5:8, find the wavelength of absorbed light (in Å) : [hc=12400 eVÅ]

Knowledge Check

  • A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.

    A
    `3xx10^(20)s^(-1)`
    B
    `2xx10^(-20)s^(-1)`
    C
    `2xx10^(20)s^(-1)`
    D
    `1xx10^(-20)s^(-1)`

    • Similar Questions

    Explore conceptually related problems

    A certain dye absorbs 4000 Å and fluoresces at 8000 Å. These being wavelengths of maximum absorption that under given conditions 50 % of the absorbed energy is emitted. Calculate the ratio of the no. of quanta emitted to the number absorbed.

    A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb.

    A 200 W sodium street lamp emits yellow light of wavelength 0.6 μm. Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

    A photon of 300 nm is absorbed by a gas which then re-emits photon .One re-emited photon has a wavelength of 400 nm .Calculate the energy of the other photon re-emitted not

    Two source of light emit X - rays of wavelenght 1 nm and visible light of wavelength 500 nm respectively . Both the source emit light of the same power 200 W. The ratio of the number density of photons of X - rays to the number density of photons of the visible light of the given wavelengths

    A modern 200 W sodium street lamp emits yellow light of wavelength 0.6 mum . Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

    A modern 200 W sodium street lamp emits yellow light of wavelength 0.6 mum . Assuming it to be 25% efficient in converting electrical energy to light, the number of photons of yellow light it emits per second is

    Home
    Profile