Home
Class 12
PHYSICS
A block of mass 2 kg rests on a rough in...

A block of mass 2 kg rests on a rough inclined plane making an angle of `30^(@)` with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

A

`9.8 B`

B

`0.7xx9.8 xxsqrt(3)N`

C

`9.8 xxsqrt(3)N`

D

`0.7 xx 9.8 N`

Text Solution

Verified by Experts

The correct Answer is:
a
Since ,`mu m g cos theta gt m g sin theta` force of friction is `f=m g sin theta`
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION TO VECTORS & FORCES

    VMC MODULES ENGLISH|Exercise JEE Main ( ARCHIVE ) ( LEVEL-1)|12 Videos

  • GRAVITATION

    VMC MODULES ENGLISH|Exercise JEE Advance (Archive) TRUE/FALSE|1 Videos

  • JEE MAIN - 5

    VMC MODULES ENGLISH|Exercise PART I : PHYSICS (SECTION - 2)|5 Videos

Similar Questions

Explore conceptually related problems

A block rests on a rough inclined plane making an angle of 30^@ with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10N, the mass of the block (in kg) is

A block rests on a rough inclined plane making an angle of 30^(@) with horizontal. The coefficient of static friction between the block and inclined plane is 0.8 . If the frictional force on the block is 10 N , the mass of the block in kg is (g = 10 m//s^(2))

A block of mass 2 kg rests on a rough inclined plane making an angle of 30° with the horizontal. If mu_(S)= 0.6 , what is the frictional force on the block ?

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block of mass 5 kg rests on a inclined plane at an angle of 30^(@) with the horizontal. If the block just begins to slide, then what is the coefficient of static friction between the block and the surface?

A block of mass m=2kg is resting on a rough inclined plane of inclination of 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block is lying on an inclined plane which makes an angle of 60^@ with the horizontal. If coefficient of friction between the block and the plane is 0.25 and g = 10 ms^(-2) , the acceleration of block when it is moves along the plane will be