find the potential difference between th point A and B and between the point B and C of figure in steady state.

Answer

B

Explanation

Two capacitor of `3 muF` each and two capacitor of `1 muF` each are in parallel
Therefore ,simplified circuit can be drawn as below
In steady no current will follow in the circuit and capacitor are fully charged.
Point A,B and C in original circuit are shown in the simplified circuit Between point A and C `6 muF` and `2 muf` are in series 100 V is applied across this series combination in series potential are drops in inverse ratio of capacity.`therefore V_(AB)=V 6 muF=(2/(6+2))xx100=25V,V_(BC)=V_2muF=(6/(6+2))xx100-75V`